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2 years ago

Consider the function, f(x) = 3x - 3. Determine the asymptote for the function f(x).

Mathematics

1 answer:

Natali [406]2 years ago

5 0

Answer:

Y= 1

Step-by-step explanation:

Given the expression f(x) = 3x - 3.

To solve for the asymptote y

Firstly we need to solve for x

3x-3=0

3x=3

x= 3/3

x=1

Hence the asymptote of the function y=1

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Value of the pronumeral and describe the rule.<br>4,1,-2,p,-8,-11

Citrus2011 [14]

Answer:

p = -5

every element in the sequence is created by subtracting 3 from the pervious element.

Step-by-step explanation:

I am not sure you put every necessary information here.

but I'd the visible information is truly everything, then it's is trivial.

the difference between 4 and 1 is ... well, -3. meaning we subtract 3 from 4 to get 1.

we suspect this is the rule and keep trying.

1 -3 = -2

hey it works.

and -8 -3 = -11

hey, also correct.

and the difference between -2 and -8 is -6, and when we place another item in between (p), we cut that in half again to -3. so, it is all consistent.

therefore,

p = -2 -3 = -5

the rule is

an = an-1 - 3

6 0

2 years ago

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Mars2501 [29]

Answer:

A.) 40.506 cm is the answer

7 0

2 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

2 years ago

PLEASE HELP ME UNDERSTAND! I don’t know how to find.... ML , CD, AC, UW (one explanation is ok too)

nlexa [21]

Step-by-step explanation:

So the way you do this is if it says 'Find AC' and on the angle you see different letters connect then on the lines and name the angle

More that 90°= Obtuse

90° angle= 90° angle

Less than a 90° angle= isosolines angle

4 0

1 year ago

-2(-5x+5) - 3x + 4= -34 solve for x

geniusboy [140]

Answer:

x = -4

Step-by-step explanation:

-2(-5x+5) - 3x + 4= -34

10x - 10 -3x + 4 = -34

7x - 6 = -34

7x = -28

x = -4

4 0

1 year ago

Read 2 more answers