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Mkey [24]
3 years ago
12

Identify the transformation that was applied to this boomerang

Mathematics
1 answer:
Marrrta [24]3 years ago
8 0

Answer:

c- translation

Step-by-step explanation:

it just moved a few points down

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The drama department needs to raise at least 575.00 for a trip to see a play they have already 163.00 if they sell candybars for
olga2289 [7]

Answer:

330

Step-by-step explanation:

575 - 163 = 412

412 / 1.25 = 329.6

Since we need to exceed the goal and we can only sell whole candy bars, we round 329.6 up to 330.

3 0
2 years ago
Can someone help me write the equations and solve, please.
Novay_Z [31]

Answer:

Number 11: She has to add 5/36 of a cup

Number 12: The present costs $22,2

Number 13: 56,7 pounds is the weight of the package.

Number 14: You started with 40 muffins

Step-by-step explanation:

<u>Number 11</u>: 1/4 = 9/36  and 1/9 = 4/36

3*1/4  -  3*1/9  = 3*9/36  - 3*4/36  = 5/36

<u>Number 12:</u> 13,32/x= 3/5 ( or 0,6)

x = 13,32/0,6 = 22,2

<u>Number 13:</u> x * 5/7 = 40,5

x = 40,5/ (5/7) or 40,5 * 7/5 = 283,5/5 = 56,7

<u>Number 14:</u> 12/x = 3/10 (or 0,30)

x= 12/0,30 = 40

6 0
3 years ago
PLEASE HELP ITS MY TRIMESTER TEST MY MOM WILL KILL ME IF I FAIL! &lt;3 WILL MARK BRAINLIST!
Artyom0805 [142]

Answer:

r =2.9985yd

Step-by-step explanation:

Given that the circumference of a circle is 2\pir

where r is the radius and \pi = 3.1415926....

You have

2\pir = 18.84 yd

2(3.1415926)r = 18.84 yd

6.2831r = 18.84yd

divide through by 6.2831

r = 2.9985yd = aprox 3yds

7 0
2 years ago
The formula for the area of a triangle is A-1bh. Solve for b.
Nady [450]

Answer:

<h2>b = <u>2A</u></h2><h2>       h</h2><h2 />

Step-by-step explanation:

A = 1/2 b h

A2 = b h

b = <u>2A</u>

      h

5 0
3 years ago
Read 2 more answers
Find the surface area of x^2+y^2+z^2=9 that lies above the cone z= sqrt(x^@+y^2)
Mashcka [7]
The cone equation gives

z=\sqrt{x^2+y^2}\implies z^2=x^2+y^2

which means that the intersection of the cone and sphere occurs at

x^2+y^2+(x^2+y^2)=9\implies x^2+y^2=\dfrac92

i.e. along the vertical cylinder of radius \dfrac3{\sqrt2} when z=\dfrac3{\sqrt2}.

We can parameterize the spherical cap in spherical coordinates by

\mathbf r(\theta,\varphi)=\langle3\cos\theta\sin\varphi,3\sin\theta\sin\varphi,3\cos\varphi\right\rangle

where 0\le\theta\le2\pi and 0\le\varphi\le\dfrac\pi4, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is \dfrac3{\sqrt2}. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

\varphi=\cos^{-1}\left(\dfrac{\frac3{\sqrt2}}3\right)=\cos^{-1}\left(\dfrac1{\sqrt2}\right)=\dfrac\pi4

Now the surface area of the cap is given by the surface integral,

\displaystyle\iint_{\text{cap}}\mathrm dS=\int_{\theta=0}^{\theta=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}\|\mathbf r_u\times\mathbf r_v\|\,\mathrm dv\,\mathrm du
=\displaystyle\int_{u=0}^{u=2\pi}\int_{\varphi=0}^{\varphi=\pi/4}9\sin v\,\mathrm dv\,\mathrm du
=-18\pi\cos v\bigg|_{v=0}^{v=\pi/4}
=18\pi\left(1-\dfrac1{\sqrt2}\right)
=9(2-\sqrt2)\pi
3 0
2 years ago
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