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andre [41]
2 years ago
12

the perimeter of a rectangle is 66 cm and its width is half its length. what are the length and the width of the rectangle?

Mathematics
2 answers:
Sauron [17]2 years ago
8 0
P = 2(l + w)

w = l/2

Plug in 'l/2' for 'w' in the equation with '66':

66 = 2(l + l/2)

66 = 2l + 2l/2

66 = 2l + l

66 = 3l

22 = l

So the length is 22.

Now plug this in to find the width.

66 = 2(22 + w)

66 = 44 + 2w

22 = 2w

11 = w

So the width is 11, and the length is 22.
jok3333 [9.3K]2 years ago
8 0
Let's set width = w

Then length = 2w

We can set up the equation:

2(w+ 2w) = 66

2(3w) = 66

6w = 66

w = \frac{66}{6} = \boxed{11}

Then we plug in:

l = 2w = 2(11) = \boxed{22}

Hope this helps :)

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Based on the information in the table what is the probability of being a girl and choosing lemonade?
tresset_1 [31]

Using it's concept, it is found that the probability of being a girl and choosing lemonade is given by:

b. 0.2.

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5 0
2 years ago
There are 25 students in a class and 10 of the students past their algebra test what percentage of the students pass to the test
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6 0
3 years ago
HELP ASAP PLSSSSSSSSSSSS
ludmilkaskok [199]

Answer:

f = .39

Step-by-step explanation:

d (v) = 2.15 v^2 / (64.4 f)

v = 40

d = 138

substitute these in

138 = 2.15 (40)^2 / (64.4 *f)

simplify

138 = 2.15 (*1600) / (64.4 *f)

138 = 3440 / (64.4 *f)

multiply each side by 64.4f

138 * 64.4 f = 3440

8887.2 f = 3440

divide by 8887.2

8887.2 f /8887.2= 3440/8887.2

f=.38707

to the nearest hundredth

f = .39

8 0
3 years ago
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