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Anuta_ua [19.1K]
3 years ago
6

I need the word for this definition..... a number is the product of that number and any whole number

Mathematics
1 answer:
Oxana [17]3 years ago
4 0
The answer to that definition is a multiple. A multiple is any number that is not zero.

Hope I helped!

- Amber
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Write an equation of a line that is parallel to 3x+2y=6 that passes through the points (4,2)
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The answer to the question

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SOMEONE HELP!! 30 points!
Nostrana [21]

Answer:

AB = square root of 403

Step-by-step explanation:

use the pythagorean theorem to solve for AB.

a^2 + b^2 = c^2

9^2 + b^2 = 22^2

81 + b^2 = 484

b^2 = 484 - 81

b^2 = 403

b = 20.07

6 0
3 years ago
If the ordered pairs graphed are all equivalent ratios, what ordered pair is missing?
Ganezh [65]

On the graph we have points x:y of

3:5

6:10

12:20

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3 years ago
Read 2 more answers
The data below represent the weight, in kilograms, of 15 containers shipped from
Nikolay [14]

Answer:

(A) Maximum = 100 kg.

(B) Lower quartile = 55 kg.

(C) Minimum = 45 kg.

(D) Upper quartile = 93 kg.

(E) Median = 81 kg.

Step-by-step explanation:

A box-plot, also known as a box and whisker plot is a method to demonstrate the distribution of a data-set based on the following 5 number summary,

  1. Minimum (shown at the bottom of the chart)
  2. First Quartile (shown by the bottom line of the box)
  3. Median (or the second quartile) (shown as a line in the center of the box)
  4. Third Quartile (shown by the top line of the box)
  5. Maximum (shown at the top of the chart).

The data provided for the weight, in kilograms, of 15 containers shipped from  a factory in one week is as follows:

S = {45, 51, 53, 55, 55, 65, 75, 81, 84, 87, 93, 93, 95, 96, 100}

The data is already arranged in ascending order.

The maximum value is:

Maximum = 100 kg.

The first quartile is the median value of the first half of the data.

The first half of the data is:

S₁ = {45, 51, 53, 55, 55, 65, 75}

The median of this data set is the middle value, i.e. 4th value.

So, the  first quartile is:

Lower quartile = 55 kg.

The minimum value is:

Minimum = 45 kg.

The third quartile is the median value of the second half of the data.

The second half of the data is:

S₂ = {84, 87, 93, 93, 95, 96, 100}

The median of this data set is the middle value, i.e. 4th value.

So, the third quartile is:

Upper quartile = 93 kg.

The The median of the data set is the middle value, i.e. the 8th value.

Median = 81 kg.

6 0
3 years ago
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