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4 years ago

A pyramid with a square base has a volume of 120 cubic meters and a height of 10 meters. what is a side length of the base?

1 answer:

4 0

Volume of Square Based Pyramid = (1/3)*(Side Length of Base)^2 *(height)

the given information are:
Volume = 120
height = 10

plug this in and get:
120 = (1/3)*(side)^2 *(10)
12 = (1/3)*(side)^2 [divided both sides by 10]
36 = (side)^2 [multiplied both sides by 3]
(side) = 6 [square rooted both sides]

Therefore the Side Length of the Base is 6 meters.

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What are the x and y-intercepts of the line described by this equation? -6x+3y=18.9?

Naddika [18.5K]

The "x" intercept is found when you plug in "0" for "y"
-6x + 3(0) = 18.9
-6x = 18.9 (Divide both sides by -6)
x = - 3.15
(-3.15, 0) is your x-intercept

Now plug in "0" for the x
-6(0) + 3y = 18.9
3y = 18.9 (Divide both sides by 3)
y = 6.3
(0, 6.3) is your y - intercept

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4 years ago

The altitude of an equilateral triangle is 22 inches. Find the perimeter of the equilateral triangle. Leave answer as a simplifi

torisob [31]

The perimeter of the equilateral triangle will be 76.2 in

<u>Explanation:</u>

Altitude of an equilateral triangle, H = 22 in

Perimeter, p = ?

Let a be the side of the triangle

We know:

$H = \frac{a\sqrt{3} }{2} \\\\22 = \frac{a\sqrt{3} }{2} \\\\a = 25.4 in$

Perimeter = 3a

P = 3 X 25.4 in

P = 76.2 in

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3 years ago

ur a HS photographer taking pictures fir 2 classes of 21 students each. on average, each individual pic takes 3 minutes and a cl

goblinko [34]

2 classes of 21 students each
21 × 2 classes = 42 students in total
42 × 3 mins = 126 minutes for 42 students
10 mins for 2 class pics = 20 minutes
126 + 20 = 146 minutes = 2 hours and 26 minutes

It should take 146 minutes (2 hours and 26 minutes) to take all the pictures.

6 0

3 years ago

Consider the following points on cartesian plane. A (1;2) BC3; 1) and CG-3; 4) prove that Points A, B and C are collinear.

Arlecino [84]

Step-by-step explanation:

Collinear points have the same gradient

find the gradient(slope) between AB first

$= \frac{1 - 2}{3 - 1} \\ = \frac{ - 1}{2}$

Find the one for BC

$= \frac{4 - 1}{ - 3 - 3} \\ = \frac{3}{ - 6} \\ = \frac{ - 1}{2}$

Find the gradient between AC now

$= \frac{4 - 2}{ - 3 - 1} \\ = \frac{2}{ - 4} \\ = \frac{ - 1}{2}$

YOUR LAST STATEMENT NOW WILL BE

POINTS A,B AND C ARE COLLINEAR SINCE THE GRADIENTS BETWEEN THEM IS THE SAME!!!

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2 years ago

The measure of angle 3 is 42°.<br><br> What is the measure of angle 1 in degrees?

polet [3.4K]

Answer:

<1 = 48

Step-by-step explanation:

<1 + <2 + <3 = 180 since they form a line

<1 + 90+ 42 =180

Combine like terms

<1 + 132 =180

Subtract 132 from each side

<1 +132-132 =180-132

<1 = 48

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3 years ago