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STALIN [3.7K]
3 years ago
12

In order to estimate the height of a building, two students stand at a certain distance from the building at street level. from

this point, they find the angle of elevation from the street to the top of the building to be 39°. they then move 300 feet closer to the building and find the angle of elevation to be 50°. assuming that the street is level, estimate the height of the building to the nearest foot
Mathematics
1 answer:
enyata [817]3 years ago
4 0
Let h represent the height of the building. Then the difference between the two angle measurement locations is
.. h/tan(39°) -h/tan(50°) = 300 ft
.. h = (300 ft)/(1/tan(39°) -1/tan(50°))
.. h ≈ 758 ft

The height of the building is about 758 feet.
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When asked to determine if a set of points on a graph represents a function or a relation, explain what influences your decision
ladessa [460]
You see if the graphs passes the vertical line test.
if any vertical line passes through more than one part of the graph then its not a function - just a relation.
7 0
2 years ago
What's 80/100 times $90
Fofino [41]

Answer:

72

Step-by-step explanation:

Well to make life easier just simplify the fraction

80/100 could be simplified to 4/5

4/5*90 is 72

7 0
3 years ago
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In a normal distribution, what is the probability that a data value will fall below the 
Serga [27]

Answer:

A 99.96%

Step-by-step explanation:

The z score shows by how many standard deviations the raw score is above or below the mean. The z score is positive if the raw score is above the mean while the z score is negative if the raw score is below the mean. The z score is given by:

z=\frac{x-\mu}{\sigma} \\\\where\ z=z-score,\ x=raw\ score,\mu=mean, \ \sigma=standard\ deviation\\\\For\ a\ sample\ size(n):\\\\z=\frac{x-\mu}{\sigma/\sqrt{n} }

The probability can be gotten from the normal distribution table. Therefore from the normal table:

P(z < 3.37) = 0.9996 = 99.96%

8 0
2 years ago
Sam bought two CDs for $13 each. Sales tax for both CDs was $3. Write an expression to show how much Sam paid in all.
gizmo_the_mogwai [7]
Let's see...
13x2+2x3

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8 0
3 years ago
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23. A certain type of gasoline is supposed to have a mean octane rating of at least 90. Suppose measurements are taken on of 5 r
Nostrana [21]

Answer:

a) p_v =P(Z          

b) Since p_v we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

c) P(\bar X >90)=1-P(Z

1-P(Z

d) For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}

And if we solve for n we got:

n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3

Step-by-step explanation:

Previous concepts  and data given  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

We can calculate the sample mean and deviation with the following formulas:

\bar X = \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}

\bar X=88.96 represent the sample mean    

s=1.011 represent the sample standard deviation  

n=5 represent the sample selected  

\alpha significance level    

State the null and alternative hypotheses.    

We need to conduct a hypothesis in order to check if the mean is less than 90, the system of hypothesis would be:    

Null hypothesis:\mu \geq 90    

Alternative hypothesis:\mu < 90    

If we analyze the size for the sample is < 30 and we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:    

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}}  (1)    

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".    

Calculate the statistic  

We can replace in formula (1) the info given like this:    

z=\frac{88.96-90}{\frac{0.8}{\sqrt{5}}}=-2.907      

Part a

P-value  

First we need to calculate the degrees of freedom given by:

df=n-1=5-1 = 4

Then since is a left tailed test the p value would be:    

p_v =P(Z    

Part b

Since p_v we can reject the null hypothesis at the significance level given. So based on this we can commit type of Error I.

Because Type I error " is the rejection of a true null hypothesis".

Part c

We want this probability:

P(\bar X

The best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X >90)=1-P(Z

1-P(Z

Part d

For this case we need a z score that accumulates 0.02 of the area on the right tail and 0.98 on the left tail and this value is z=2.054

And we can use this formula:

2.054=\frac{90-89}{\frac{0.8}{\sqrt{n}}}

And if we solve for n we got:

n = (\frac{2.054 *0.8}{1})^2=2.7 \approx 3

7 0
3 years ago
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