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Alex_Xolod [135]
3 years ago
14

marta is trying to decide between two jobs the first job will pay 35,340 and the second job will pay 36,120 before taxes which j

ob will give Marta a higher net salary
Mathematics
2 answers:
Makovka662 [10]3 years ago
8 0
Martha will get a higher salary with the first option because the more you make the more taxes are taken out of your salary
timurjin [86]3 years ago
3 0
The first option $35,340
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The results of a standardized test are normally distributed. The mean test score is 312. Of the scores, 16% are under 307. What
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Zhang is designing protective packaging. He tests his design by dropping a raw egg protected by his packaging from various heigh
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Read 2 more answers
A sample of 26 offshore oil workers took part in a simulated escape exercise, and their escape time (unit: second) were observed
Anuta_ua [19.1K]

Answer:

t=\frac{370.69-360}{\frac{24.36}{\sqrt{26}}}=2.238  

The degrees of freedom are given by:

df = n-1= 26-1=25

And the p value would be:

p_v =P(t_{25}>2.238)=0.0172  

If we use a 5% of significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 360 second or 6 minutes. We need to be careful since if we use a significance level of 1% the result change

Step-by-step explanation:

Information given

\bar X=370.69 represent the sample mean

s=24.36 represent the sample standard deviation

n=26 sample size  

\mu_o =6*60 =360 s represent the value to verify

z would represent the statistic

p_v represent the p value

Hypothesis to test

We want to check if the true mean is at most 360 seconds, the system of hypothesis would be:  

Null hypothesis:\mu \leq 360  

Alternative hypothesis:\mu > 360  

The statistic for this case would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}} (1)  

We can replace in formula (1) the info given like this:  

t=\frac{370.69-360}{\frac{24.36}{\sqrt{26}}}=2.238  

The degrees of freedom are given by:

df = n-1= 26-1=25

And the p value would be:

p_v =P(t_{25}>2.238)=0.0172  

If we use a 5% of significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 360 second or 6 minutes. We need to be careful since if we use a significance level of 1% the result change

4 0
3 years ago
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