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Kobotan [32]
3 years ago
8

What is the greatest common multiple for 14,21

Mathematics
1 answer:
Fiesta28 [93]3 years ago
7 0

Answer:

the greatest common multiple of 14 and 21 is 7.

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The beads in 7 bracelets if 4 bracelets have 96 bead
Naya [18.7K]
96/4=24 beads in 1 bracelet
beads in 7 bracelets = 24*7=168
3 0
3 years ago
Evaluate the expression below at x = 5. x/35 + 5x^2
kramer

Answer:

876/7

Step-by-step explanation:

Just plug the number 5 into the equation and solve. Remember your Order of Operations (PEMDAS).

4 0
2 years ago
Please help please please please
tankabanditka [31]

Answer:

b

Step-by-step explanation:

the hypotenuse is equal to the square root of 2 times x in a 45 45 90 right triangle

the square root of 2 times the square root of 2 cancels out to equal 2 and 2 times 3 is 6 so the hypotenuse equals 6

7 0
3 years ago
What is the variable in the expression below?<br><br><br> 9.X
Ludmilka [50]

Answer:

The variable in that expression is x

5 0
3 years ago
Read 2 more answers
C(x)=0.4x^2-208x+37,365. what is the minimum cost of manufacturing dresses?
statuscvo [17]
2nd degree and in form ax^2+bx+c it is a prabola the minimum cost is the vertex (every parabola has only one, min or max) minimum cost is the vertex vertex=-b/(2a) a=0.4 b=-208 vertex=-(-208)/(2*0.4) vertex=208/0.8 vertex=260 (means 260 dresses) that is x value subsitute for y value C(x)=0.4(260)^2-208(260)+37365 C(x)=10325 minimum cost is $10,325
6 0
4 years ago
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