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Lesechka [4]
3 years ago
5

30 points please help urgent

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
7 0

2.

x = 2

3.

x = 50

HOPE THIS WILL HELP YOU

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Use distributive property to rewrite each algebraic expression: 15(2+r)
ira [324]

Answer:

15 x 2 + 15 x r

Step-by-step explanation:

I hope this helps and hope u have an Amazing day!!

8 0
3 years ago
Can be interpreted as the number of standard deviations a data value is from the mean of all the data values.
Elza [17]
Hello, what you are looking for is the term z-score. z-score is the standardized score that has been developed for statistics to compare data from different scales. By using the mean and standard deviation of the data values, a z-score is calculated and comparisons can be deduced even if the two data sets have different scales.

For example, if a z-score is 1.33, then it is 1.33 standard deviations from the mean. This result is more typical compared to a z-score of 3 meaning that it is 3 standard deviations from the mean.
5 0
3 years ago
Area and distributive property 14-5
blondinia [14]
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3 0
3 years ago
The quantity of a drug Q mg present in the body t hours after an injection of the drug is given is : Q = f (t) = 70 te-0.6tFind
solniwko [45]

Answer:

A) f(1) =38.43mg

B) f'(1) = -15.37 mg/hour

C) f(6) = 11.47mg

D) f'(6) = -4.97mg/hour

F) 23.06mg

H) 0

Step-by-step explanation:

Given the function:

Q = 70te^-0.6t........(1)

Where Q is measured in mg and t is in hours

(A) f(1) is the quantity Q in mg after 1 hour

f(1) = 70(1)e^-0.6(1) = 70e^-0.6

= 70×0.5488

= 38.43 mg

(B) f'(1) = dQ/dt, at t=1

= 70t × -0.6e^-0.6t +70e^-0.6t

= -42te^-0.6t + 70e^-0.6t

= -42(1) × 0.5488 + 70 × 0.5488

=28 × 0.5488

= -15.37mg/hour

(C) f(6) = 70te^-0.6t

= 70(6)e^-0.6(6)

= 420e^-3.6

= 420 × 0.0273

= 11.47mg

(D) f'(6) = dQ/dt, at t= 6

f' = -42te^-0.6t + 70e^-0.6t

f'(6) = -42(6)e^-3.6 + 70e^-3.6

= -252 × 0.0273 + 70 × 0.0273

= -6.8796 + 1.911

= -4.9686

= -4.97mg/hour

(E) f(1) is the quantity of the drug present in the body 1 hour after injection.

f'(1) is the rate of decrease of the drug 1 hour after injection or it is the rate at which the drug is decreasing 1 hour after injection.

(F) The quantity Q is given by

Q= 38.43 - 15.37

= 23.06mg

(G) f(6) is the quantity of the drug present in the body 6 hours after injection

f'(6) is the rate at which the drug is removed or decreased from the body 6 hours after injection.

(H) The quantity is given by

Q = 11.47 - 4.97×6

Q= 11.47-29.82

Q= -18.35mg

This is not possible, hence after 6 hours of injection the quantity of drug remaining is zero.

5 0
3 years ago
What is the value of x in the equation 6(x+7.8) =−12?
Fynjy0 [20]

Answer:

x = -9.8

Step-by-step explanation:

6(x+7.8) =−12

Divide each side by 6

6/6(x+7.8) =−12/6

(x+7.8) =−2

Subtract 7.8 from each side

x+7.8-7.8 = -2-7.8

x = -9.8

3 0
2 years ago
Read 2 more answers
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