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shtirl [24]
3 years ago
13

Please help i will give brainliest!!

Mathematics
1 answer:
Romashka-Z-Leto [24]3 years ago
4 0
5.78x10^7
If you need an explanation on how then let me know :)
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Could some one pllz give me real answers
timofeeve [1]

Answer:

See below

Step-by-step explanation:

You just need 1/4 of everything:

1/4 c peanut butter

1/4 c brown sugar

1/4 c gran sugar

1/4 c butter

1/2 egg

1/4 tsp baking soda

1/4 tsp baking powder

1/4 tsp vanilla

5/8 c flour

8 0
3 years ago
Read 2 more answers
2) In a set of data that show a normal distribution the mean is 7.8 and the standard deviation is 1.7. What is the proportion of
abruzzese [7]
First, we get the z-score using formula:
z =( X - μ ) / σ

From the problem, we substitute the given values:
z = (9 - 7.8) / 1.7
z = 0.71

From the z-table (one-tailed), for a z-score of 0.7059, the proportion of numbers that are greater than 9 is  0.76.
6 0
3 years ago
Find a solution of the linear inequality.<br> y&gt;_4x-5
irga5000 [103]

Answer:

(0,0) is among the solutions

Step-by-step explanation:

The given inequality is y\ge4x-5

A solution to this inequality is any ordered pair that satisfies the inequality.

Let us check for x=0 and y=0

We substitute to get:

0\ge4*0-5

0\ge-5....This is true.

Therefore (0,0) is a solution to the given inequality.

There are infinitely many solutions.

4 0
3 years ago
Help me please I need help!
nordsb [41]

Answer:

I'd say A because this question is just like y and xays.

Step-by-step explanation:

8 0
4 years ago
Read 2 more answers
What are the zeros of the quadratic function f(x) = 6x2 – 24x + 1?<br><br> fast please
xxTIMURxx [149]

Answer:      6(x²-4x+4-4)+1=0, 6(x-2)²-24+1=0, 6(x-2)²=23, x-2=±√(23/6), x=2±√(23/6)=2±1.95789, so x=3.95789 or 0.04211 approx. these are the zeros.

step by step explanation:

\boxed{\boxed{\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}}}

Solution-

The quadratic function is,

6x^2-24x + 1

a = 6, b = -24, c = 1

x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

=\dfrac{-(-24)\pm \sqrt{-24^2-4\cdot 6\cdot 1}}{2\cdot 6}

=\dfrac{24\pm \sqrt{576-24}}{12}

=\dfrac{24\pm \sqrt{552}}{12}

=\dfrac{24\pm 2\sqrt{138}}{12}

=\dfrac{12\pm \sqrt{138}}{6}

=\dfrac{12+\sqrt{138}}{6},\ \dfrac{12-\sqrt{138}}{6}

4 0
4 years ago
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