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netineya [11]
3 years ago
9

A gardener works for 13 hours during a week and charges $169 how much does the gardener charge for each hour?​

Mathematics
1 answer:
bonufazy [111]3 years ago
7 0

Answer:

You have to divide to unit price, 169/13 is equal to 13!

Step-by-step explanation:

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It has been observed that some persons who suffer acute heartburn, again suffer acute heartburn within one year of the first epi
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Answer:

We conclude that the true percentage of those in the first group who suffer a second episode is less than or equal to the true percentage of those in the second group who suffer a second episode.

Step-by-step explanation:

We are given that there are 31 people in the first group and this group will be administered the new drug. There are 45 people in the second group and this group will be administered a placebo.

After one year, 11% of the first group has a second episode and 9% of the second group has a second episode.

<em>Let </em>p_1<em> = </em><u><em>true percentage of those in the first group who suffer a second episode.</em></u>

<em />p_2<em> = </em><u><em>true percentage of those in the second group who suffer a second episode.</em></u>

So, Null Hypothesis, H_0 : p_1-p_2\leq 0  or  p_1\leq p_2      {means that the true percentage of those in the first group who suffer a second episode is less than or equal to the true percentage of those in the second group who suffer a second episode}

Alternate Hypothesis, H_A : p_1-p_2 > 0  or  p_1>p_2      {means that the true percentage of those in the first group who suffer a second episode is more than the true percentage of those in the second group who suffer a second episode}

The test statistics that will be used here is <u>Two-sample z proportion test</u> <u>statistics</u>;

                              T.S. = \frac{(\hat p_1-\hat p_2)-(p_1-p_2)}{\sqrt{\frac{\hat p_1(1-\hat p_1)}{n_1}+ \frac{\hat p_2(1-\hat p_2)}{n_2}} }  ~ N(0,1)

where, \hat p_1 = sample proportion of people in the first group who suffer a second episode = 11%

\hat p_2 = sample proportion of people in the second group who suffer a second episode = 9%

n_1 = sample of people in first group = 31

n_2 = sample of people in second group = 45

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<em>Now, at 0.1 significance level, the z table gives critical value of 1.2816 for right-tailed test.</em><em> Since our test statistics is less than the critical value of z as 0.283 < 1.2816, so we have insufficient evidence to reject our null hypothesis due to which </em><em><u>we fail to reject our null hypothesis</u></em><em>.</em>

Therefore, we conclude that the true percentage of those in the first group who suffer a second episode is less than or equal to the true percentage of those in the second group who suffer a second episode.

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Answer:

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