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Gemiola [76]
3 years ago
6

Rembrandt framed his masterpiece. The painting by itself is a rectangle with length 20 \text{ cm}20 cm20, start text, space, c,

m, end text and width 16 \text{ cm}16 cm16, start text, space, c, m, end text. The painting and frame together form a larger rectangle with length 25 \text{ cm}25 cm25, start text, space, c, m, end text and width 20 \text{ cm}20 cm20, start text, space, c, m, end text. Find the area of the frame. Assume no overlap between the frame and painting.
Mathematics
1 answer:
mojhsa [17]3 years ago
4 0

Answer:

Step-by-step explanation:84% of a contractor’s jobs involves electrical work. 75% of a contractor’s jobs involve plumbing work. Of the jobs that involve plumbing, 90% of the jobs also involves electrical work. Let E = jobs involving electrical work L = jobs involving plumbing work Suppose one of the contractor’s jobs is randomly selected. Using the sixth Excel worksheet, a) Find P(E). 0.84 b) Find P(L). 0.75 c) In words, what does E | L mean? d) Find P(E | L). e) Find P(E and L). f) Are E and L independent events? Why or why not? g) Find P(E or L). h) Are E and L mutually exclusive? Why or why not

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By applying z-score formula we got that if a reporter determines a mean order time of 63 minutes then value o Z is 1.19

<h3>What is standard deviation?</h3>

Standard deviation is a number used to tell how measurements for a group are spread out from the average (mean), or expected value

Here given that

The owners of an eyeglass store claim that they fill customers' orders, on average, in 60 minutes with a standard deviation of 15. 9 minutes. Based on a random sample of 40 orders, a reporter determines a mean order time of 63 minutes

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number of sample=n=40

\bar{x}=63 \\

Now we can calculate z by z-score formula as

z=\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}}  \\\\&=\frac{63-60}{\frac{15 \cdot 9}{40}} \\ \\=\frac{3}{2.5140} \\ \\=1.19\end{aligned}

By applying z-score formula we got that if a reporter determines a mean order time of 63 minutes then value o Z is 1.19

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