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3 years ago

Which of the following numbers is divisible by 3, 5, and 10?

Mathematics

2 answers:

Alex787 [66]3 years ago

8 0

Answer:

D. 30

Step-by-step explanation:

A. 15

3 and 5 are liable. 10 is not

B. 20

5 and 10 liable. 3 is not.

C. 25

5 is liable. 3 and 10 is not.

D. 30

3, 5, and 10 are liable

tatuchka [14]3 years ago

5 0

Answer: D) 30

Dividing 30 by 3 equals 10

Dividing 30 by 5 equals 6

Dividing 30 by 10 equals 3

If doing process of elimination

15

20

25

30

15 and 25 is not divisible by 10. Let’s get rid of those options

20

30

20 is not divisible by 3. This leaves the final option 30.

Hope this helps comment below for more questions :)

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Select the correct answer.

eimsori [14]

Answer:

Step-by-step explanation:

Given that

f(x)=-2x – 1

g(x) = -1/2x+1/2

I The function f( g(x)) = x for all real x.

-2(-1/2X + 1/2) - 1

X - 1 - 1

X - 2

II. The function glAx)) = x for all real x.

- 1/2( -2X - 1 ) + 1/2

X + 1/2 + 1/2

X + 1

III. Functions fand g are inverse functions

Inverse of f(x)

Y = -2x - 1

X = - 2Y - 1

- 2Y = X + 1

Y = - 1/2X - 1/2

Therefore, none of the above answers is correct.

The correct answer is therefore D

7 0

2 years ago

Read 2 more answers

Aiden's bill for lunch at a restaurant is $14.50, and he wants to leave a 18% tip.

zhannawk [14.2K]

Answer:

Tip: $2.61

Total: $17.11

Step-by-step explanation:

tip = total cost * rate of tip

Add the tip to the original bill, that's the total.

I hope this helped.

4 0

2 years ago

Every time I use a piece of scrap paper, I crumple it up and try to shoot it inside the recycling bin across the room. I'm prett

valentinak56 [21]

Using the binomial distribution, it is found that there is a 0.0012 = 0.12% probability at least two of them make it inside the recycling bin.

<h3>What is the binomial distribution formula?</h3>

The formula is:

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$C_{n,x} = \frac{n!}{x!(n-x)!}$

The parameters are:

x is the number of successes.

n is the number of trials.

p is the probability of a success on a single trial.

With 5 shoots, the probability of making at least one is $\frac{211}{243}$ , hence the probability of making none, P(X = 0), is $\frac{232}{243}$ , hence: