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Elanso [62]
3 years ago
15

HeeeeeEEEEEELP

Mathematics
1 answer:
jasenka [17]3 years ago
5 0
3(x+2)+x=2x+16
3x+6+x=2x+16
4x+6=2x+16
4x=2x+10
2x=10
x=5
The answer is d, x=5
I worked it step by step so I hope you were able to follow
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Explain How you can use base ten blocks to find 1.54 + 2.37
Elena-2011 [213]
1.54 + 2.37 

= (1 + 5/10 + 4/100) + (2 + 3/10 + 7/100)

= 1 + 5/10 + 4/100 + 2 + 3/10 + 7/100

= 3 + 8/10 + 11/100

= 3 + 8/10 + (10/100 + 1/100)

= 3 + 8/10 + (1/10 + 1/100)
= 3 + 8/10 + 1/10 + 1/100

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Given: AB with point C between A and B. AB = 10x + 20, AC = 2x + 13, and CB = 10x - 9.
Feliz [49]

Answer:46

Step-by-step explanation:

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3 years ago
Fifteen percent of an employee's taxable income is collected each paycheck. Before taxes are removed from each paycheck,
aleksklad [387]

Answer:

y = x [1-\frac{15}{100}]

Step-by-step explanation:

If the variable x represents the employee's pay before tax-exempt expenses and taxes are removed and y variable represents the employee's take-home pay after these deductions and if fifteen percent of an employee's taxable income is collected each paycheck, then y is given by

y = x [1-\frac{15}{100}]. (Answer)

For, example, an employee's payment is deducted by $350 at the rate of 15% tax and other deduction.

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James folds a piece of paper in half several times,each time unfolding the paper to count how many equal parts he sees. After fo
Snezhnost [94]

Answer:

There will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

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Let us assume the piece of paper James decides to fold is a SQUARE.

Now, let us assume:

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y : The number of parts obtained after folds.

Now, if the paper if folded ONCE ⇒  n = 1

Also, when the pap er is folded once, the parts obtained are TWO equal parts.

⇒  for n = 1 , y = 2       ..... (1)

Similarly, if the paper if folded TWICE  ⇒  n = 2

Also, when the paper is folded twice, the parts obtained are FOUR equal parts.

⇒  for n = 2 , y = 4       ..... (2)

⇒y  = 2^2  =  2^n

Continuing the same way, if the paper is folded SEVEN times  ⇒  n = 7

So, y = 2^ n = 2^7 = 128

⇒  There are total 128 equal parts.

Lastly,  if the paper is folded ELEVEN  times  ⇒  n = 11

So, y = 2^ n = 2^{11} = 2048

⇒  There are total 2048 equal parts.

Hence, there will be total 2048 parts of the given paper if James if able to fold the paper eleven times.

And the needed function is y = 2 ^n

8 0
4 years ago
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