It should be noted that the relationship is not linear based on the information illustrated as the difference between the numbers aren't the same.
<h3>How to illustrate the information?</h3>
It should be noted that an equation is simply used to illustrate and express the relationship between the variables.
It should be noted that for the relationship to be linear, it's essential that they've the same relationship between them.
When x = 1, y = 4.5. The
When x = 2, y = 6.5
When x = 3, y = 8.5
When x = 4 y = 11.5
It should be noted that there's a difference of 2 at first but between 3 and 4, there is. a difference of 3.
Therefore, the relationship is not linear.
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Answer:
B. y= -x^2+50x-300
Step-by-step explanation:
A. y^2=4x^2-100
B. y= -x^2+50x-300
C. x=-y^2-400
D. x^2=-6y^2+200
we are to find profits (y) when the company sells x items
Option A can be used to calculate the profit (y) squared
Option B can be used to calculate profits (y)
Option C can be used to calculate items sold(x)
Option D can be used to calculate items sold squared(x^2)
We are asked to find the weekly profit (y) function which eliminate options A, C and D leaving us with option B
Therefore, the weekly profits (y) function in thousands of dollars when the company sells x items is
B. y= -x^2+50x-300
Answer:
m=-3
Step-by-step explanation:
Just reflect C and D across the y-axis
C is (-4, -4) so A is (-4, 4)
D is (4, -4) so B is (4, 4)
First you need to multiply by a factor that will givr you the same value in one of the x or y value.
(6x-12y=24)1
+(-x-6y=4)-2
6x-12y=24
=2x+12y=-8
8x=16÷8
x=2
now that you have x, substitute x by 2 in one of the eqauations
-2-6y=4
+2. +2
=-6y=6
÷-6. ÷-6
y=-1
