B), A),D), and I dontknow how to answer the last one
This is a mixture problem.
Let the 9 karat gold to be mixed be x. The 18 karat would weight (200 - x). Since the total = 200g.
mass1 * karat1 + mass2*karat = total mass * total carat
Let mass1 be x g. mass 2 would be = (200 -x)
karat 1 = 9 karat 2 = 18
Total mass = 200g.
Total karat = 14.
9*x + 18*(200 -x) = 14*200
9x + 18*200 - 18*x = 14*200
18*200 + 9x - 18x = 14*200
3600 - 9x = 2800
3600 - 2800 = 9x
800 = 9x
9x = 800
x = 800/9
x ≈ 88.89
Therefore 88.89 grams of 9 karat gold must be mixed.
Answer:
I believe it is 1
Step-by-step explanation:
Answer:b
Step-by-step explanation:
Answer:
200.96
Step-by-step explanation:
So, we have to find the area of both.
The area for the mat is
(pi)12^2=3.14x144. However, since it is HALF a circle, we divide it by two.
So, 226.08
Next, the water bowl.
(3.14)4^2=50.24.
226.08-25.12=200.96
I may be wrong!
