Answer:
2
Step-by-step explanation:
Answer:
carnation $2.50; rose $3.00
Step-by-step explanation:
Let c = price of 1 carnation.
Let r = price of 1 rose.
3c + 5r = 22.5
3c + 2r = 13.50
Subtract the se3cond equation from the first equation.
3r = 9
r = 3
Now substitute r = 3 in the first equation and solve for c.
3c + 5r = 22.5
3c + 5(3) = 22.5
3c = 7.5
c = 2.5
Answer: carnation $2.50; rose $3.00
Answer:
the students that brought a lunch box is 28
Step-by-step explanation:
The computation of the students that brought a lunch box is shown below:
= Entire school students × students that carry a lunch box ÷ entering students
= 84 students × 8 ÷ 24 students
= 28 students
Hence, the students that brought a lunch box is 28
<h2>Key Ideas</h2>
<h2>Solving the Question</h2>
When both sides of the equal sign are equal, there are infinite solutions.
When you are able to isolate the variable, there is only one solution.
When the equation states an untrue expression, there is no solution.
1=3 is an untrue fact. Therefore, there would be no solutions to the system.
<h2>Answer</h2>
There is no solution