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4 years ago

7

Need help transforming one formula to another!

1 answer:

Sindrei [870]4 years ago

5 0

Hello! I don't know if this will help you any but I worked it out, got nothing on it. So, I just had my twin help me and he had nothing either. But, this is just how to find the transformation. Seems like this is already complete to me.

To find the transformation, compare the equation to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x-axis or y-axis, and if there is a vertical stretch.

Parent function : y=√a

Horizontal shift : None

Vertical shift : none

Reflection about the x-axis : none

Vertical stretch : Stretched.

I am so sorry if this doesn't help you but to me, in both my eyes and my brother's eyes, this already looks complete. I hope this helps you out. Again, so sorry if it doesn't.

-Karleif ☺

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3 years ago

A vibrating object produces periodic waves with a wavelength of 53 cm and a frequency of 15 Hz. How fast do these waves move awa

DerKrebs [107]

Answer:

v = 7.95 m/s

Explanation:

Given that,

Wavelength of a wave, $\lambda=53\ cm=0.53\ m$

Frequency of a wave, f = 15 Hz

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3 years ago

A boy throws a ball with an initial velocity of 19.6 m/s. What maximum height does the ball reach?

Wewaii [24]

<h2>Hello!</h2>

The answer is: 19.59 m

<h2>Why?</h2>

Since there is no information about the launch type, we can assume that the ball is thrown vertically upward.

When the ball reaches the maximum height, just at that moment, the velocity turns to 0, and after that moment, the ball starts falling, so:

We will use the following formula:

$Vf^2=Vi^2+2*g*s$

Where:

Vf= Final velocity = 0

Vi= Initial velocity = $\frac{19.6m}{s}$

g = Gravity Acceleration = $\frac{9.81m}{s^{2} }$

s = Traveled distance

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Have a nice day!

8 0

3 years ago

A biologist looking through a microscope sees a bacterium at r⃗ 1=2.2i^+3.7j^−1.2k^μm(1μm=10−6m). After 6.2 s , it's at r⃗ 2=4.6

stiv31 [10]

The Average velocity for the bacterium is 0.75 unit/sec.

<u>Explanation:</u>

The given values are in the vector form

Where,

dS = distance covered

dT = time interval

Now, to calculate distance covered, we have

$|d S|=\sqrt{d S^{2}}$

&

$d S=r_{2}-r_{1}$

d S=(4.6 i+1.9 k)-(2.2 i+3.7 j - 1.2 k)

d S=(4.6-2.2) i+(0-3.7) j+(1.9+1.2) k

d S=2.4 i-3.7 j+3.1 k

Now, putting these values in the standard formula to evaluate the average velocity, we get;

$v_{a v g}=\frac{|\mathrm{d} S|}{d T}$

$v(a v g)=\frac{|\sqrt{\left\{\left(2.4^{2}\right)+\left(3.7^{2}\right)+\left(3.1^{2}\right)\right\}}|}{7.2}$

As dT=7.2 sec

Now,

Solving the equation, we get;

$v(a v g)=\frac{5.390732789}{7.2}$

$\begin{aligned}&v(a v g)=\frac{5.39}{7.2}\\&v(a v g)=0.748611111\\&v(a v g)=0.75 \text { units / sec }\end{aligned}$

Hence, the average velocity for the bacterium is 0.75 unit/sec.

3 0

3 years ago