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fenix001 [56]
4 years ago
7

Need help transforming one formula to another!

Physics
1 answer:
Sindrei [870]4 years ago
5 0

Hello! I don't know if this will help you any but I worked it out, got nothing on it. So, I just had my twin help me and he had nothing either. But, this is just how to find the transformation. Seems like this is already complete to me.

To find the transformation, compare the equation to the parent function and check to see if there is a horizontal or vertical shift, reflection about the x-axis or y-axis, and if there is a vertical stretch.

Parent function : y=√a

Horizontal shift : None

Vertical shift : none

Reflection about the x-axis : none

Vertical stretch : Stretched.

I am so sorry if this doesn't help you but to me, in both my eyes and my brother's eyes, this already looks complete. I hope this helps you out. Again, so sorry if it doesn't.

-Karleif ☺

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Here, Force = m * a = 34 * 2 = 68 N

According to Newton's third law, fence will exert equal and opposite force (by direction) on the robot.

In short, Your Answer would be Option C) <span>The robot exerts a force of 68 N on the fence; the fence exerts a force of 68 N on the robot. 

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4 0
4 years ago
What is the circumference of the moon?
Fittoniya [83]

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8 0
3 years ago
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On a planet far, far ay, an astronut picks up a rock The rock has a mass of 5.00 kg and on this particular planet its weight is
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12.4 ms^{-2}

Explanation:

on the specific planet ,

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7 0
3 years ago
9: A post is being driven into the ground. The first strike drives the post 25 inches into the ground. Each additional strike dr
faltersainse [42]

Answer:

99

Explanation:

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Third strike=4/5*20=16 in

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sixth strike=4/5*10.24=8.192 in

seventh strike=4/5*8.192=6.5536 in

Total=(25+20+16+12.8+10.24+8.192+6.5536) in=98.7856 in

Taking this as a geometric series

Sum(7)=a\frac{(1-r^{7}}{1-r} where a is initial value taken as 25 for this case and r is rate taken as 4/5 or 0.8 in our case

Sum(7)=25\frac {1-0.8^{7}}{1-0.8}=98.7856 in

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3 0
4 years ago
a 2.00 kg friction-less block is attached to an ideal spring with force constant 315 N/m.Initially, the spring is neither stretc
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Answer

given,

mass of block, m = 2 Kg

spring constant, k = 315 N/m

speed of the block, v = 12 m/s

a) Amplitude of the motion

   A = v \sqrt{\dfrac{k}{m}}

   A =\dfrac{12}{\sqrt{\dfrac{315}{2}}}

         A = 0.956 m

b) maximum acceleration of the block

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  F_{max} = 301.14\ N

5 0
3 years ago
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