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leva [86]
3 years ago
11

a 2.00 kg friction-less block is attached to an ideal spring with force constant 315 N/m.Initially, the spring is neither stretc

hed nor compressed , but the block is moving in the negative direction at 12.0 m/s. find:-a) the amplitude.b) the maximum acceleration of the block.c) the maximum force the spring exerts on the block.
Physics
1 answer:
Setler [38]3 years ago
5 0

Answer

given,

mass of block, m = 2 Kg

spring constant, k = 315 N/m

speed of the block, v = 12 m/s

a) Amplitude of the motion

   A = v \sqrt{\dfrac{k}{m}}

   A =\dfrac{12}{\sqrt{\dfrac{315}{2}}}

         A = 0.956 m

b) maximum acceleration of the block

    a_{max}= A \dfrac{k}{m}

    a_{max}= 0.956\times \dfrac{315}{2}

    a_{max}= 150.57\ m/s^2

c) maximum Force

  F_{max} = m a_{max}

  F_{max} = 2\times 150.57

  F_{max} = 301.14\ N

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