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mr Goodwill [35]
3 years ago
6

What number does A stand for in this equation? 6 x 3 = (? * 5)-(? x 2)

Mathematics
2 answers:
Bas_tet [7]3 years ago
8 0
A=6. I think that is the answer
DerKrebs [107]3 years ago
3 0

Answer: A=8

Step-by-step explanation: 6x3 is equal to 24. (Ax5)-(Ax2) is equal to 6x3. 8x5 is equal to 40. 8x2 is equal to 16. 40-16 is equal to 24.

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What is the degree of 6x^3y^2
boyakko [2]

Answer:

5

Step-by-step explanation:

The largest exponent is the degree of the polynomial. Therefore, the degree is 5.

8 0
2 years ago
Read 2 more answers
A man sold a small cottage at a loss of 5%.Had he sold it at a gain of 7%,he would have got Rs480 more.Find the cost price of th
NARA [144]

Answer:

Cost price of the cattage is Rs.6857.142857...

4 0
1 year ago
Find the surface area of the cone to the nearest square unit. Use π = 3.14. radius 6cm height 9cm
almond37 [142]

The answer is A≈316.99cm²

3 0
3 years ago
In a group of a hundred and fifty students attending a youth workshop in mombasa, 125 of them are fluent in kiswahili, 135 in en
jek_recluse [69]

Answer:

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

Step-by-step explanation:

<u><em>Step(i):</em></u>-

Given total number of students n(T) = 150

Given 125 of them are fluent in Swahili

Let 'S' be the event of fluent in  Swahili language

n(S) = 125

The probability that the fluent in  Swahili language

P(S) = \frac{n(S)}{n(T)} = \frac{125}{150} = 0.8333

Let 'E' be the event of fluent in English language

n(E) = 135

The probability that the fluent in  English language

P(E) = \frac{n(E)}{n(T)} = \frac{135}{150} = 0.9

n(E∩S) = 95

The probability that the fluent in  English and Swahili

P(SnE) = \frac{n(SnE)}{n(T)} = \frac{95}{150} = 0.633

<u><em>Step(ii):</em></u>-

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = P(S) + P(E) - P(S∩E)

           = 0.833+0.9-0.633

           = 1.1

<u><em>Final answer:-</em></u>

The probability that a student chosen at random is fluent in English or Swahili.

P(S∪E) = 1.1

8 0
2 years ago
HELP <br><br>Determine whether the relation is a function<br><br> y=2w=2​
nexus9112 [7]

Answer:

Hi there!

I might be able to help you!

It is NOT a function.

<u>Determining whether a relation is a function on a graph is relatively easy by using the vertical line test. If a vertical line crosses the relation on the graph only once in all locations, the relation is a function. However, if a vertical line crosses the relation more than once, the relation is not a function</u>. <u>X = y2 would be a sideways parabola and therefore not a function.</u> Good test for function: Vertical Line test. If a vertical line passes through two points on the graph of a relation, it is <em>not </em>a function. A relation which is not a function. The x-intercept of a function is calculated by substituting the value of f(x) as zero. Similarly, the y-intercept of a function is calculated by substituting the value of x as zero. The slope of a linear function is calculated by rearranging the equation to its general form, f(x) = mx + c; where m is the slope.

A relation that is not a function

As we can see duplication in X-values with different y-values, then this relation is not a function.

A relation that is a function

As every value of X is different and is associated with only one value of y, this relation is a function.

Step-by-step explanation:

It's up there!

God bless you!

3 0
3 years ago
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