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3 years ago

Find the slope-intercept form of the equation of the line that passes through the points (2,-5)

Mathematics

1 answer:

n200080 [17]3 years ago

4 0

Answer:

-3

Step-by-step explanation:

(

$(2,-5)=(x_1,y_1) \\ (4,-11)= (x_2,y_2) \\$

$m = \frac{y_2 - y_1}{x_2 - x_1} \\$

Plug in values into the given equation

$m = \frac{ - 11 - ( - 5))}{4 - 2} \\ \\ m = \frac{ - 11 + 5}{2} \\$

Simplify

$m = \frac{ - 6}{2} \\ m = - 3$

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10. Rotate the figure shown 180° clockwise. Record the coordinates of the 3 points image.

inna [77]

Answer:

$J' = (6,7)$

$K' = (6,2)$

$L'=(3,7)$

Step-by-step explanation:

From the attachment, we have:

$J = (-6,-7)$

$K = (-6,-2)$

$L = (-3,-7)$

Rotation: 180 degrees clockwise

Required

Find J', K' and L'

When a point (x, y)is rotated 180 degree clockwise, the resulting point is: (-x, -y)

So, we have:

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3 0

3 years ago

Does the quadratic have a maximum or minimum

STALIN [3.7K]

Answer:

B)max/ opens down

Step-by-step explanation:

Parabola equation:

The equation of a parabola has the following format:

$y = ax^2 + bx + c$

If $a > 0$ , that is, x² is multiplied by a positive number, the function has a minimum value and the parabola opens up.

If $a < 0$ , that is, x² is multiplied by a negative number, the function has a maximum value and the parabola opens down.

In this question:

$y = -x^2 - 2x + 3$

From the graph, we already see that it opens down and has a max, and analitically, since $a = -1 < 0$ , this is confirmed. The correct answer is given by option b.

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