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3 years ago

Find the slope-intercept form of the equation of the line that passes through the points (2,-5)

Mathematics

1 answer:

n200080 [17]3 years ago

4 0

Answer:

-3

Step-by-step explanation:

(

$(2,-5)=(x_1,y_1) \\ (4,-11)= (x_2,y_2) \\$

$m = \frac{y_2 - y_1}{x_2 - x_1} \\$

Plug in values into the given equation

$m = \frac{ - 11 - ( - 5))}{4 - 2} \\ \\ m = \frac{ - 11 + 5}{2} \\$

Simplify

$m = \frac{ - 6}{2} \\ m = - 3$

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Identify the center and radius from the equation of the circle given below. x^2+y^2+121-20y=-10x

Tcecarenko [31]

Answer:

Center: (-5,10)

Radius: 2

Step-by-step explanation:

The equation of the circle in center-radius form is:

$(x-h)^2+(y-k)^2=r^2$

Where the point (h,k) is the center of the circle and "r" is the radius.

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$x^2+y^2+121-20y-121=-10x-121\\x^2+y^2-20y=-10x-121$

Add 10x to both sides:

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Make two groups for variable "x" and variable "y":

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Complete the square:

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Add $(\frac{20}{2})^2=10^2$ inside the parentheses of "y".

Add $5^2$ and $10^2$ to the right side of the equation.

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$(h,k)=(-5,10)$

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