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ryzh [129]
3 years ago
5

Find the slope-intercept form of the equation of the line that passes through the points (2,-5)

Mathematics
1 answer:
n200080 [17]3 years ago
4 0

Answer:

-3

Step-by-step explanation:

(

(2,-5)=(x_1,y_1) \\ (4,-11)= (x_2,y_2) \\

m =  \frac{y_2 - y_1}{x_2 - x_1}  \\

Plug in values into the given equation

m =  \frac{ - 11 - ( - 5))}{4 - 2}  \\  \\ m =  \frac{ - 11 + 5}{2}  \\

Simplify

m =  \frac{ - 6}{2}  \\ m =  - 3

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10. Rotate the figure shown 180° clockwise. Record the coordinates of the 3 points<br> image.
inna [77]

Answer:

J' = (6,7)

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Step-by-step explanation:

From the attachment, we have:

J = (-6,-7)

K = (-6,-2)

L = (-3,-7)

Rotation: 180 degrees clockwise

Required

Find J', K' and L'

When a point (x, y)is rotated 180 degree clockwise, the resulting point is: (-x, -y)

So, we have:

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3 0
3 years ago
Does the quadratic have a maximum or minimum
STALIN [3.7K]

Answer:

B)max/ opens down

Step-by-step explanation:

Parabola equation:

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y = ax^2 + bx + c

If a > 0, that is, x² is multiplied by a positive number, the function has a minimum value and the parabola opens up.

If a < 0, that is, x² is multiplied by a negative number, the function has a maximum value and the parabola opens down.

In this question:

y = -x^2 - 2x + 3

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