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-Dominant- [34]
3 years ago
6

A spherical ball just fits inside a cylindrical can that is 10 centimeters tall, with a diameter of 10 centimeters. Which expres

sion gives the volume of the sphere, in cubic centimeters?

Mathematics
1 answer:
valentinak56 [21]3 years ago
3 0

Check the picture below.

\bf \textit{volume of a sphere}\\\\ V = \cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r = 5 \end{cases}\implies V=\cfrac{4\pi (5)^3}{3} \\\\\\ V=\cfrac{500\pi }{3}\implies V\approx 523.6

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For the cut glass pieces to be rectangular in shape, the glass cutter should ensure:

  1. All four interior angles = 90° each.
  2. Opposite sides are parallel and equal to each other.
  3. Diagonals should be of the same length and should bisect each other.

<h3>Properties of a Rectangle</h3>
  • All four angles of a rectangle are 90° each.
  • There are two pairs of parallel sides that are equal in length.
  • The diagonals bisect each other and are of equal length.

Thus, to ensure the cut glass pieces are rectangular in shape, he should ensure the following:

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  2. The opposite sides should be parallel and equal to each other.
  3. The diagonals should be of the same length and should bisect each other.

Learn more about properties of rectangle on:

brainly.com/question/2835318

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Answer:

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Step-by-step explanation:

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Use the sum and difference identities to find the exact values of the sine, cosine, and tangent of the angle. . 165 = 135 + 30
Serhud [2]
So lets get to the problem 

<span>165°= 135° +30° </span>

<span>To make it easier I'm going to write the same thing like this </span>
<span>165°= 90° + 45°+30° </span>

<span>Sin165° </span>
<span>= Sin ( 90° + 45°+30° ) </span>
<span>= Cos( 45°+30° )..... (∵ Sin(90 + θ)=cosθ </span>
<span>= Cos45°Cos30° - Sin45°Sin30° </span>

<span>Cos165° </span>
<span>= Cos ( 90° + 45°+30° ) </span>
<span>= -Sin( 45°+30° )..... (∵Cos(90 + θ)=-Sinθ </span>
<span>= Sin45°Cos30° + Cos45°Sin30° </span>


<span>Tan165° </span>
<span>= Tan ( 90° + 45°+30° ) </span>
<span>= -Cot( 45°+30° )..... (∵Cot(90 + θ)=-Tanθ </span>
<span>= -1/tan(45°+30°) </span>
<span>= -[1-tan45°.Tan30°]/[tan45°+Tan30°] </span>

<span>Substitute the above values with the following... These should be memorized </span>
<span>Sin 30° = 1/2 </span>
<span>Cos 30° =[Sqrt(3)]/2 </span>
<span>Tan 30° = 1/[Sqrt(3)] </span>
<span>Sin45°=Cos45°=1/[Sqrt(2)] </span>
<span>Tan 45° = 1</span>
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