Ask question

Ask question

All categories

-Dominant- [34]

3 years ago

6

A spherical ball just fits inside a cylindrical can that is 10 centimeters tall, with a diameter of 10 centimeters. Which expres

sion gives the volume of the sphere, in cubic centimeters?

1 answer:

valentinak56 [21]3 years ago

3 0

Check the picture below.

$\bf \textit{volume of a sphere}\\\\ V = \cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r = 5 \end{cases}\implies V=\cfrac{4\pi (5)^3}{3} \\\\\\ V=\cfrac{500\pi }{3}\implies V\approx 523.6$

You might be interested in

Solve: x + 1 < 5<br>Me confused and need help

natita [175]

Answer: x < 4

Step-by-step explanation: You are trying to isolate the variable, x, so you have to subtract 1 on both sides of the inequality. Then, you are left with x < 4.

4 0

3 years ago

Michael has 105 credits at an arcade. He wants to purchase a drink and play his favorite video game with his credits. If the dri

seraphim [82]

He can play his game 12 times
Explanation: 105-63=42
42 divided by 3.5=12

4 0

3 years ago

"the value of x is:" <br> 1) 7<br> 2) 7√3<br> 3) 14<br> 4) 14√3<br> 5) 7√2

gizmo_the_mogwai [7]

Answer:

the base/width is 7

Step-by-step explanation:

it is 7 because it is half the length from corner to corner

5 0

3 years ago

Kissie needs to paint the top and sides of a rectangular prism. the prism has a length of 25 mm, a width of 15 mm, and a height

MariettaO [177]

Area total = 1,095 mm2, hoped this helped :D

6 0

3 years ago

Read 2 more answers

The set of points (-3, 4), (-1, 1), (-3,-2), and (-5,1) identifies the vertices of a quadrilateral. Which is the most specific d

KIM [24]

Answer:

Option (4). Rhombus

Step-by-step explanation:

From the figure attached,

Distance AB = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}$

= $\sqrt{(1-4)^2+(-5+3)^2}$

= $\sqrt{(-3)^2+(-2)^2}$

= $\sqrt{13}$

Distance BC = $\sqrt{(4-1)^2+(-3+1)^2}$

= $\sqrt{9+4}$

= $\sqrt{13}$

Distance CD = $\sqrt{(-2-1)^2+(-3+1)^2}$

= $\sqrt{9+4}$

= $\sqrt{13}$

Distance AD = $\sqrt{(1+2)^2+(-5+3)^2}$

= $\sqrt{9+4}$

= $\sqrt{13}$

Slope of AB ( $m_{1}$ ) = $\frac{y_{2}-y_{1}}{x_{2}-x_{1}}$

= $\frac{4-1}{-3+5}$

= $\frac{3}{2}$

Slope of BC ( $m_{2}$ ) = $\frac{4-1}{-3+1}$

= $-\frac{3}{2}$

If AB and BC are perpendicular then,

$m_{1}\times m_{2}=-1$

But it's not true.

[ $m_{1}\times m_{2}=(\frac{3}{2})(-\frac{3}{2})$ = - $\frac{9}{4}$ ]

It shows that the consecutive sides of the quadrilateral are not perpendicular.

Therefore, ABCD is neither square nor a rectangle.

Slope of diagonal BD = $\frac{4+2}{-3+3}$

= Not defined (parallel to y-axis)

Slope of diagonal AC = $\frac{1-1}{-1+5}$

= 0 [parallel to x-axis]

Therefore, both the diagonals AC and BD will be perpendicular.

And the quadrilateral formed by the given points will be a rhombus.

5 0

3 years ago