The distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.
<h3>Probability</h3>
a. Distribution
X ~ N (20 , 6)
b. P(x ≤24)
= P[(x - μ ) / σ (24 - 20) / 6]
= P(z ≤0.67)
= 0.74857
=0.7486
Hence:
Probability = 0.7486
c. P(21 < x < 26)
= P[(21 - 26)/ 6) < (x - μ ) / σ < (24 - 20) / 6) ]
= P(-0.83 < z < 0.67)
= P(z < 0.67) - P(z < -0.)
= 0.74857- 0.2033
= 0.54527
Hence:
Probability =0.54527
d. Using standard normal table ,
P(Z < z) = 66%
P(Z < 0.50) = 0.66
z = 0.50
Using z-score formula,
x = z× σ + μ
x = 0.50 × 6 + 20 = 23
23 Christmas cards
Therefore the distribution of X is X ~ N (20 , 6) and the probability that this American will receive no more than 24 Christmas cards this year is 0.7486.
Learn more about probability here:brainly.com/question/24756209
#SPJ1
your almost right check once and you wil get especially alternate angles
Gavin earns more because he earns 20 per hour and eva earns 11.5 per hour.
So Gavin earns 8.50 more than eva.
Hope this helps :)
Answer:
x^3 + 1/x^3 = 488
Step-by-step explanation:
- x^2 + 1/x^2 = 62
- x^2 + 1/x^2 + 2 = 64
- ( adding 2 in both sides )
- (x + 1/x ) ^2 = 64
- x + 1/x = 8
now,
- ( x+ 1/x ) ^ 3 = 512
- x^3 + 1/x^3 + 3 × x × 1/x ( x + 1/x )
- x^3 + 1/x^3 + 3 ( 8 )
- ( since x + 1/x = 8 )
- x^3 + 1/x^3 + 24 = 512
- x^3 + 1/x^3 = 488
hence, we got x^3 + 1/x^3 = 488
Yes, all whole numbers are integers, no matter negative or positive.
