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3 years ago

7

the temperature in Indianapolis was-4°F at 7:00 am. the temperature rose 3°F by noon. What was the temperature at noon? use a nu

mber line to find the answer

1 answer:

Nostrana [21]3 years ago

3 0

I believe that it would be -1

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Solve for v.<br> 3v = 42<br> Simplify your answer as much as possible.

pogonyaev

Answer:

V=14

Step-by-step explanation:

3v=42 divide both sides by 3. getting v=14

3 0

2 years ago

Y = -x+5y=−x+5y, equals, minus, x, plus, 5

Serga [27]

The answer is D
Hope this hel

6 0

2 years ago

30 points for the correct answer

Dahasolnce [82]

Answer:

its either 2/9 or 2/3

Step-by-step explanation:

I solved the top part and got 2/3 and i solved the bottom part and got 1/3 and you can multiply 2/3 and 1/3 and got 2/9

3 0

2 years ago

I am offering another 100 points

Ivahew [28]

Answer:

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

Step-by-step explanation:

<u>Perfect squares</u>: 4, 9, 16, 25, 36, 49, 64, 81, 100, 121, ...

To find $\sf \sqrt{75}$ , identify the perfect squares immediately <u>before</u> and <u>after</u> 75:

64 and 81

$\begin{aligned}\sf As\;\; 64 < 75 < 81\; & \implies \sf \sqrt{64} < \sqrt{75} < \sqrt{81}\\&\implies \sf \;\;\;\;\;8 < \sqrt{75} < 9 \end{aligned}$

$\sf Since \;\sqrt{\boxed{64}}=\boxed{8}\;and\;\sqrt{\boxed{81}}=\boxed{9}\; \textsf{it is known that $\sqrt{75}$ is between}\\\\\sf \boxed{8}\;and\;\boxed{9}\;.$

See the attachment for the correct placement of $\sf \sqrt{75}$ on the number line.

6 0

10 months ago

Read 2 more answers

3. Use the diagram 2 and 3 are ____ angles 1. complementary 2. vertical 3. right 4. supplementary

Vladimir79 [104]

#3

2 and three are supplementary angles .

#4.

The answer is opposite angles .

Hence there is no option

#5

Bisected angles are equal

$\\ \sf\longmapsto 5x=3x+10$

$\\ \sf\longmapsto 5x-3x=10$

$\\ \sf\longmapsto 2x=10$

$\\ \sf\longmapsto x=\dfrac{10}{2}$

$\\ \sf\longmapsto x=5$

Now

m<ABC

$\\ \sf\longmapsto 5x+3x+10$

$\\ \sf\longmapsto 8x+10$

$\\ \sf\longmapsto 8(5)+10$

$\\ \sf\longmapsto 40+10$

$\\ \sf\longmapsto 50$

5 0

2 years ago

Read 2 more answers