The probabability of winning on at least 1 bet is equal to 1 less the probaility of not winning on either of the 6 bets.
The probability of not wining on any bet is independent of winning or not winning on any of the bets, so the combined probability is calculated as the product of each individual probability.
Each indivitual probability of not winning the is:
(number of not winning outcomes) / (number of possible outcomes) = 37 / 38.
Then, the combined probability of not winning the six times is: (1/38)*(37/38)*(37/38)*(37/38)*(37/38)*(37/38) =(37/38)^6
Therefore, the probability of winning at least one bet is:
= 1 - (37/38)^6 ≈ 1 - 0.973684 ≈ 0.03.
Answer: 0.03.
equation form: y = mx + b
where m is the slope, and b is the y-intercept.
slope = (y2 - y1) / (x2 - x1) = (13 -8) / (11 - 5) = 5/6
y = 5/8 x + b (replace x and y by 5 and 8)
=> 8 = 5/6 * 5 + b
=> 8 = 25/6 + b
=> b = 8 - 25/6 = 23/6
==> equation: y = 5/6 * x + 23/6
<h2>There is no 4 odd digits that will add up to 19.</h2>
Answer:
I think 478.4 ._.
Step-by-step explanation:
First, find out how many gallons of gasoline she can buy with $18.50 by dividing 18.50 by 1.25 to get 14.8 gallons. Then, since he already has 6 gallons in his tank, add 6 to 14.8 = 20.8. Finally multiply this by the ratio of gallons to miles (23) to get 478.4
