Answer:
The journal entry to be recorded for the payment of the note on date of maturity is shown below:
Explanation:
The journal entry to be recorded for the payment of the note on date of maturity is as follows:
Notes Payable A/c..........................Dr $9,000
Interest expense A/c......................Dr $148
Cash A/c..........................................Cr $9,148
Being payment of the note payable is reported on the maturity date
As on the day of the payment, the cash is going out of the business which means assets is decreasing and any decrease in assets is credited. Therefore, the cash account is credited. And the notes payable is paid so the notes payable account is debited and interest expense account will also be debited.
Working Note:
Interest expense = $9,000 × 10% × 60/ 365
Interest expense = $148
Answer and Explanation:
a. The computation of cost of ending work in process inventory for materials, conversion, and in total is shown below:-
For material = 2,080 × $15.66
= $32,572.80
For conversion = 930 × $6.23
= $5,793.90
For total cost of work in process inventory = $32,572.80 + $5,793.90
= $38,366.70
b. The computation of cost of the units completed and transferred out for materials, conversion, and in total is shown below:-
For material = 21,700 × $15.66
= $339,822
For Conversion = 21,700 × $6.23
= $135,191
For total cost of completed and transferred units = $339,822 + $135,191
= $475,013
Transnet SOC Ltd is a rail, port, and pipeline company in Johannesburg.
Price: This company is a price maker, therefore, in terms of price, Transnet perfect compitetor is a price taker.
Output: Transnet has the ability to decide the quantity of their output and they have many competitors on this one.
<span>Profit: Transnet might be able to increase their profit but in a competition it would be hard because customers might switch to the competitor. </span>
Answer:
0.17
Explanation:
The computation of the expected return on investment is shown below:
= (Expected return of the outcome 1 × Probability of the outcome 1) + (Expected return of the outcome 1 × Probability of the outcome 1) + (Expected return of the outcome 1 × Probability of the outcome 1)
= (0.15× 0.50) + (0.25 × 0.30) + (0.10 × 0.20)
= 0.075 + 0.075 + 0.02
= 0.17
