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Vaselesa [24]
3 years ago
13

Jill Barkely obtained a 25-year, $460,000 mortgage loan from University Savings and Loan Association with 6% interest. The month

ly payment is $2,962.40. For the first payment, find the payment to principal to the nearest cent.
Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0
<span>If you have a $460,000 loan at 6% interest for 25 years; payments should be $2,963.79, not $2962.40. At $2,963.79, $2,300 would be interest, $663.79 would be principal. After that first payment your balance would be $459,336.21.
Hope I helped!!</span>
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Answer:

Total time = 56.81/60 + 59.22/60 + 57.39/60 + 60.11/60 = 3.89 minutes

Average Time in Minutes = 3.89 min / 4 = 0.97 minutes

Average Time in Seconds = 0.97 *60 = 58.38 Seconds

Step-by-step explanation:

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What is the value of x in the equation 1/5x – 2/3y = 30, when y = 15?
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Answer:

x = 200

Step-by-step explanation:

1/5x – 2/3y = 30

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1.On which number line are –4 and its opposite shown?2.Which of the following describes the location of the opposite of the numb
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1. d

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8 0
3 years ago
How would you determine the axis of symmetry in order to graph x^2 = 8y^2.
Tanya [424]
The picture illustrates the definition. The point P is a typical point on the parabola so that its distance from the directrix, PQ, is equal to its distance from F, PF. The point marked V is special. It is on the perpendicular line from F to the directix. This line is called the axis of symmetry of the parabola or simply the axis of the parabola and the point V is called the vertex of the parabola. The vertex is the point on the parabola closest to the directrix.

Finding the equation of a parabola is quite difficult but under certain cicumstances we may easily find an equation. Let's place the focus and vertex along the y axis with the vertex at the origin. Suppose the focus is at (0,p). Then the directrix, being perpendicular to the axis, is a horizontal line and it must be p units away from V. The directrix then is the line y=-p. Consider a point P with coordinates (x,y) on the parabola and let Q be the point on the directrix such that the line through PQ is perpendicular to the directrix. The distance PF is equal to the distance PQ. Rather than use the distance formula (which involves square roots) we use the square of the distance formula since it is also true that PF2 = PQ2. We get

<span>(x-0)2+(y-p)2 = (y+p)2+(x-x)2. 
x2+(y-p)2 = (y+p)2.</span>If we expand all the terms and simplify, we obtain<span>x2 = 4py.</span>

Although we implied that p was positive in deriving the formula, things work exactly the same if p were negative. That is if the focus lies on the negative y axis and the directrix lies above the x axis the equation of the parabola is

<span>x2 = 4py.</span><span>The graph of the parabola would be the reflection, across the </span>x<span> axis of the parabola in the picture above. A way to describe this is if p > 0, the parabola "opens up" and if p < 0 the parabola "opens down".</span>

Another situation in which it is easy to find the equation of a parabola is when we place the focus on the x axis, the vertex at the origin and the directrix a vertical line parallel to the y axis. In this case, the equation of the parabola comes out to be

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Parabolas in standard positionIn this demonstration we show how changing the value of p changes the shape of the parabola. We also show the focus and the directrix. Initially, we have put the focus on the y axis. You can select on which axis the focus should lie. Also you may select positive or negative values of p. Initially, the values of p are positive. 

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