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Vaselesa [24]
3 years ago
13

Jill Barkely obtained a 25-year, $460,000 mortgage loan from University Savings and Loan Association with 6% interest. The month

ly payment is $2,962.40. For the first payment, find the payment to principal to the nearest cent.
Mathematics
1 answer:
Dmitrij [34]3 years ago
5 0
<span>If you have a $460,000 loan at 6% interest for 25 years; payments should be $2,963.79, not $2962.40. At $2,963.79, $2,300 would be interest, $663.79 would be principal. After that first payment your balance would be $459,336.21.
Hope I helped!!</span>
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15. Fatima bought a video game that has a
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Answer:

Step-by-step explanation:

Discount = 15% of 45

=\frac{15}{100}*45\\\\=\frac{675}{100}=6.75

= $6.75

Price of the video game = 45 - 6.75 = $38.25

Tax = 7%of 38.25

=\frac{7}{100}*38.25\\\\=\frac{267.75}{100}=2.6775

Price paid by Fatima for the video game = 38.25 + 2.68 = $ 40.93

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Answer:

4.6

Step-by-step explanation:

4 0
2 years ago
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Which is equivalent sin^-1 (cos(pi/2))?Give your answer in radians
NNADVOKAT [17]

Answer:

Given the expression: \sin^{-1}(\cos(\frac{\pi}{2}))

Let the value of the given expression in radians be \theta

then;

\sin^{-1}(\cos(\frac{\pi}{2})) =\theta

\cos \frac{\pi}{2} = \sin \theta              ......[1]

We know the value of \cos \frac{\pi}{2} = 0

Substitute the given value in [1] we have;

\sin \theta = 0

Since, the value of \sin \theta is 0, therefore, the value of \theta is in the form of:

\theta = n\pi ; where n is the integer.

At n =0, 1 and 2, {Since, n is the integer}

Value of  \theta =0, \pi and 2\pi

therefore, the answer in radians either   0 , \pi or 2\pi


6 0
3 years ago
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The city of Orlando’s building a dog park in downtown Orlando dog park will be triangular shaped as shown on the coordinate plan
kiruha [24]

Answer:

Perimeter of the dog park = 15.4 yards

Step-by-step explanation:

Coordinates of the vertices of the given triangle are,

P(1, 2), Q(1, 6), R(-4, 2)

Since distance between the two points (x_1, y_1) and (x_2,y_2) is,

d = \sqrt{(y_2-y_1)^2+(x_2-x_1)^2}

Length of PQ = \sqrt{(1-1)^2+(2-6)^2}

PQ = 4

Length of PR = \sqrt{(1+4)^2+(2-2)^2}

PR = 5

Length of QR = \sqrt{(1+4)^2+(6-2)^2}

QR = \sqrt{25+16}

     = \sqrt{41}

     = 6.4 yards

Therefore, perimeter of the given triangle = PQ + QR + PR

                                                                       = 4 + 6.4 + 5

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4 0
3 years ago
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