The dP/dt of the adiabatic expansion is -42/11 kPa/min
<h3>How to calculate dP/dt in an adiabatic expansion?</h3>
An adiabatic process is a process in which there is no exchange of heat from the system to its surrounding neither during expansion nor during compression
Given b=1.5, P=7 kPa, V=110 cm³, and dV/dt=40 cm³/min
PVᵇ = C
Taking logs of both sides gives:
ln P + b ln V = ln C
Taking partial derivatives gives:
Substitutituting the values b, P, V and dV/dt into the derivative above:
1/7 x dP/dt + 1.5/110 x 40 = 0
1/7 x dP/dt + 6/11 = 0
1/7 x dP/dt = - 6/11
dP/dt = - 6/11 x 7
dP/dt = -42/11 kPa/min
Therefore, the value of dP/dt is -42/11 kPa/min
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Answer:
Step-by-step explanation:
we have that
The scale drawing is
we know that
Using proportion find out the actual dimensions of the volleyball court
Let
x -----> drawing court lengths in cm
y ----> court lengths in cm
For x=40 cm
For x=80 cm
Find the equation for the proportional relation ship between drawing court lengths x in centimeters and court lengths in y centimeters
A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form 
or 
For x=40 cm, y=900
substitute
-----> 
The equation is
7x-99=2x+1
5x=100
x=20
mark me brainliest if the answer is correct, thank you in advance :)
Answer:
a = 0,-7
Step-by-step explanation:
a^2 + 7a=0
Factor out an a
a(a+7) =0
Using the zero product property
a=0 a+7 =0
a =0 a= -7
Answer:
a = 50°, b = 130°, c = 20°
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Sum the 3 angles in the right triangle
a + 40° + 90° = 180°
a + 130° = 180° ( subtract 130° from both sides )
a = 50°
a and b are adjacent angles and sum to 180° , so
a + b = 180°
50° + b = 180° ( subtract 50° from both sides )
b = 130°
Then sum the angles in the top triangle, that is
30° + 130° + c = 180°
160° + c = 180° ( subtract 160° from both sides )
c = 20°
