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grandymaker [24]
2 years ago
13

Logd(x-3)-2=0 Please help me change this to exponetial form

Mathematics
1 answer:
saul85 [17]2 years ago
8 0

Answer:

the answer is the same as it is.

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PLZ HELP ME ASAP<br> algebra 2 word problem
Ostrovityanka [42]

Give each month a number:

January = 0

February = 1

March = 2

April = 3

Now set X to 3 in the equation ad solve for t.

t = -30cos(x/6) +60

t = -30cos(3/6) +60

t = 33.672 degrees. ( Round as necessary)

You would need to change the +60 to a new starting point based on what the rise in temperature is due to global warming.

8 0
3 years ago
A circular swimming pool has a diameter of 40 meters. The depth of the pool is constant along west-east lines and increases line
Nataliya [291]

Answer:

Volume is 2000\pi\ m^{3}

Solution:

As per the question:

Diameter, d = 40 m

Radius, r = 20 m

Now,

From north to south, we consider this vertical distance as 'y' and height, h varies linearly as a function of y:

iff

h(y) = cy + d

Then

when y = 1 m

h(- 20) = 1 m

1 = c.(- 20) + d = - 20c + d              (1)

when y = 9 m

h(20) = 9 m

9 = c.20 + d = 20c + d                  (2)

Adding eqn (1) and (2)

d = 5 m

Using d = 5 in eqn (2), we get:

c = \frac{1}{5}

Therefore,

h(y) = \frac{1}{5}y + 5

Now, the Volume of the pool is given by:

V = \int h(y)dA

where

A = r\theta

A = rdr\ d\theta

Thus

V = \int (\frac{1}{5}y + 5)dA

V = \int_{0}^{2\pi}\int_{0}^{20} (\frac{1}{5}rsin\theta + 5) rdr\ d\theta

V = \int_{0}^{2\pi}\int_{0}^{20} (\frac{1}{5}r^{2}sin\theta + 5r}) dr\ d\theta

V = \int_{0}^{2\pi} (\frac{1}{15}20^{3}sin\theta + 1000) d\theta

V = [- 533.33cos\theta + 1000\theta]_{0}^{2\pi}

V = 0 + 2\pi \times 1000 = 2000\pi\ m^{3}

7 0
3 years ago
What is the point-slope form equation of the graph?
sammy [17]

Answer:

y-4= 1/2(x+2)

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!
BARSIC [14]

It be 81.

You have to take half of -18 which is -9, and square that, which is 81.

8 0
3 years ago
If (4 to the 4 power) to the x power = 4 to the 32 power, what is the value of x?
gizmo_the_mogwai [7]

(4 to the 4 power) to the x power = 4 to the 32 power

(4^4)^x = 4^32

4^4x = 4^32

4x = 32

 x = 8

Answer

x = 8

8 0
2 years ago
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