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Eva8 [605]
3 years ago
12

If you help you get brianilist

Mathematics
1 answer:
Ket [755]3 years ago
4 0
Hi There!!!!!!!!

To find the area of this triangle:

Use this rule :
 Area of a triangle= 1/2 * base * height
 base: 10 in
height:8in

1/2*10*8= 40in
 The correct answer is definately  40in.

Hope this helped u!!! p.s please id appreciate brainliest.

~TRUE BOSS

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chuck earned $76 mowing lawns.the gas for the mower cost $12 and he bought a new string for the trimmer for $7.write and find th
Harlamova29_29 [7]
76 - 12 = 64 - 7 = 57
3 0
3 years ago
Solve for x.
liubo4ka [24]

Answer:

the answer is 4

Step-by-step explanation:i hope im right sry if im not

8 0
3 years ago
Read 2 more answers
Determine whether is a right triangle for the given vertices. Explain. Q(7, –10), R(–3, 0), S(9, –8)
andriy [413]

Answer:

Yes, It is a right triangle for the given vertices.

Step-by-step explanation:

Given:

Q(7, –10),

R(–3, 0),

S(9, –8)  

To Find:

determine whether is a rig ht triangle for the given vertices = ?

Solution:

QR=\sqrt{(-3-7)^2+(0-(-10))^2}

QR=\sqrt{(-10)^2+(10)^2}

QR=\sqrt{100+100}

QR=\sqrt{200}--------------------------(1)

QR=14.142136

RS=\sqrt{(9-(-3))^2+(-8-0)^2}

RS=\sqrt{(12)^2+(-8)^2}

RS=\sqrt{144+64}

RS=\sqrt{208}---------------------------(2)

RS=14.422205

QS=\sqrt{(7-9)^2+(-10-(-8))^2}

QS=\sqrt{(-2)^2+(-2)^2}

QS=\sqrt{4+4}

QS=\sqrt{8}-------------------------------------(3)

QS=2.828427

According to Pythagorean Theorem,

RS^2 = QR^ +QS^2

Substituting the values,

(\sqrt{208})^2 = (\sqrt{200})^2 +(\sqrt{8})^2

208 = 200 +8

208 = 208

Pythagorean theorem is satisfied. Hence it is a right triangle.

8 0
3 years ago
I don’t get this please help ASAP
jek_recluse [69]

Answer:

AE = 70

Step-by-step explanation:

Given that ACE is a triangle and B , D , F are mid-points of AC, CE, AE respectively.

⇒ BF, FD, BD are mid-segments.

Mid-segment is a line segment joining mid points of two sides of a triangle,

And it as two properties :

1) mid-segment is always parallel to the third side

2) mid-segment is half in length of the third side

⇒ Here, BD is the mid-segment and is parallel to third side AE

And also BD is half of AE

⇒ AE = 2×BD = 2×35

⇒ AE = 70.    

3 0
3 years ago
What is the solution to the system of equations? y=2/3x+3 x = –2
aliya0001 [1]

Answer:

(-2, 5/3)

Step-by-step explanation:

Step 1: Write out systems of equations

y = 2/3x + 3

x = -2

Step 2: Substitution

y = 2/3(-2) + 3

y = -4/3 + 3

y = 5/3

Step 3: Write solution

(-2, 5/3)

6 0
3 years ago
Read 2 more answers
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