Answers: D for it represents the diameter and A for represents the radius
Answer:
D. two real solutions
Step-by-step explanation:
p²+5 = 6p
p² - 6p +5 =0
D = b² - 4ac = (-6)² - 4*(1)*5 = 36 - 20 = 16
D > 0, so this equation has 2 real solutions
Answer:
2.92
Step-by-step explanation:
Normal price
4 * 6.98 =27.92
Sale price
2 for 12.50 means 4 at 2* 12.50
2*12.50 = 25
Subtract
27.92-25=2.92
He saved 2.92
The intervals are given as follows:
- In range notation: [-282, 20,320].
- In set-builder notation: {x|x ∈ ℝ, -282 <= x <= 20,320}
<h3>What is the range of elements notation for interval?</h3>
The range of elements notation for interval is given by:
[a,b].
In which:
In this problem these values are given by:
a = -282, b = 20,320.
Hence the interval in range notation is given by:
[-282, 20,320].
<h3>How to write the interval in set-builder notation?</h3>
The same interval can be written as follows, using set-builder notation?
{x|x ∈ ℝ, a <= x <= b}
Hence, for the situation described in this problem, the set-builder notation for the values is:
{x|x ∈ ℝ, -282 <= x <= 20,320}
More can be learned about notation of intervals at brainly.com/question/27896097
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Answer:
The Alans's average for the course is 84.5
Step-by-step explanation:
We are given
There are 4 tests, A Term paper and a Final examination.
Score = 92, 78, 82, 90.
Term paper score = 80
Final examination score = 86
Weighted mean = ∑ w.f/∑w
also the sum of all the weights is 100% = 1
weighted mean = 15%*92 + 15%*78+15%*82+15%*90+20%*80+20%*86/1
= 51.3 + 33.2
= 84.5
Therefore the Alans's average for the course is 84.5
