Answer:
(-5,6)
Step-by-step explanation:
G(-5,4)=(x1,y1)
H(-5,8)=(x2, y2)
midpoint=?
now,
(x,y)= x1+x2/2 y1+y2/2
-5-5/2 4+8/2
-10/2 12/2
-5 6
therefore the co ordinates of midpoint are(-5,6)
The only possible answer is
X= 0
Hope this is correct and good luckk!!!! :)
You need to provide an equation for this to be solved
He first two are relatively easy. f(x-2) shifts it sideways (2 to the right in this case) f(x) -2 shifts it straight down (by 2)
f(2x) means replace x with 2x in the original 4(2x + 1)^2 − 3 if you factor out the 2 from the square root you get 4*sqr(2) ( x + ½)^2 - 3 which is now in the form a ( x -h)^2 + k the vertex is now at (-½, -3) (it used to be at (-1,-3) the "a" has gotten bigger, which makes the parabola "skinnier" (it goes up faster)
2•f(x) becomes 2*( 4(x + 1)2 − 3 ) = 8 (x+1)^2 -6 where is the vertex now? is this parabola fatter or skinnier than the original f(x) ?
The second and the third one because first is the same as 3 4/7 and 81=3^4
