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Lynna [10]
2 years ago
8

The value of 3 x 10, when x = 2, can be

Mathematics
1 answer:
forsale [732]2 years ago
6 0

Answer:

ujiuhgufxzfjzkgdlhckgfiyditdoydoydktdktdkydjgx

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Fix the inequality below to correctly show the domain of<br> the function.
Nataliya [291]

Answer:

from questions it is given that X is lies between the -9 and -5. In this question X lies only between -9 to -5 but -9 and -5 are excluded because there is no equal sign given in the question. so value of X are (-8,-7,-6). and plot in the graph .and these values are the component of X so they are also a domain.

6 0
2 years ago
ANSWER ASAP PLEASE!!!
Thepotemich [5.8K]

area of triangle = 1/2(3)(4) = 6 in^2

area of rectangle = 3 x 10 = 30 in^2

area of trapezoid = 1/2(3+5)(2) = 8 in^2


area of the figure: 6 in^2 + 30 in^2 + 8 in^2 = 44 in^2


answer

44 in^2

3 0
2 years ago
Read 2 more answers
PENISPENISPENISPENISPENISPENISPENIS
Sindrei [870]

Answer:

penispenispenispeinis

3 0
3 years ago
Read 2 more answers
If f(x) = x + 3 and g(x) = -7x + 7, which statement is true? Click on the correct answer. 5 is in the domain of fºg. 5 is not in
Studentka2010 [4]

Answer:

man you got this

Step-by-step explanation:

If f(x) = x + 9 and g(x) = 9x – 4, - 22024651. ... Click on the correct answer. 3 is not in the domain of fºg. 3 is in the domain of fºg. 1. See answer. Add answer+5 pts ... Answer: 3 is in the domain of f(g(x)). Step-by-step explanation: ... What is the domain of the given function? a) {x | x = –6, –1, 0, 3}; {y | y = –7, –2, ...

The domain is all real numbers except 9 (positive)

This is because we can't have 0 in the denominator, and when x equals 9, then the denominator is 0. Anything divided by 0 is undefined, which is why 9 (in this equation) is not included.

3 0
3 years ago
The venticles of a right angle are a[0,4], b[3,-2] c[-3, -4] Find It's area.​
givi [52]

Answer:

The area of this triangle is about 21.2132 square units.

Step-by-step explanation:

First, find the lengths of the legs AB and BC.

Length of AB ===

Find the difference in position vertically:

-2-4=-6

The points are 6 units apart vertically.

Find the difference in position horizontally:

3-0=3

The points are 3 units apart horizontally.

These lengths form a right triangle with the distance between the points as the hypotenuse, so you can use the pythagorean theorem to solve:

a^2+b^2=c^2\\3^2+6^2=c^2\\9+36=c^2\\45=c^2\\c\approx6.7082

AB is about 6.7082 units long.

Length of BC ===

Same process as above.

Find the vertical distance:

-4--2=-2

2 units apart vertically.

Find the horizontal distance:

-3-3=-6

6 units apart horizontally.

Use the pythagorean theorem:

2^2+6^2=c^2\\4+36=c^2\\40=c^2\\c=6.3246

BC is about 6.3246 units long.

Area ===

Finally, you can use these to find the area of the triangle. The area of a right triangle is just half the area of a rectangle with the same base and height:

A=\frac{b\times h}{2}\\\\A=\frac{6.7082\times6.3246}{2}\\\\A=\frac{42.4264}{2}\\\\A=21.2132

The area of this triangle is about 21.2132 square units.

4 0
2 years ago
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