How do you find the value of variable b and c? The value of variable a is 62.5
1 answer:
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-1
7(4÷7)-5
Write the division as a fraction
4-5
-1
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7(4÷7)-5
Write the division as a fraction
4-5
-1
hope it helps..
Answer:
The answer to the question is
The longest interval in which the given initial value problem is certain to have a unique twice-differentiable solution is (-∞, 4)
Step-by-step explanation:
To apply look for the interval, we divide the ordinary differential equation by (t-4) to
y'' + y' +
y =
Using theorem 3.2.1 we have p(t) = , q(t) =
, g(t) =
Which are undefined at 4. Therefore the longest interval in which the given initial value problem is certain to have a unique twice-differentiable solution, that is where p, q and g are continuous and defined is (-∞, 4) whereby theorem 3.2.1 guarantees unique solution satisfying the initial value problem in this interval.