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pickupchik [31]
3 years ago
8

In a school there are 600 teachers ad 1200 students

Mathematics
1 answer:
8_murik_8 [283]3 years ago
8 0

Answer:

Can you please give a clearer explanation of what is your question?

Step-by-step explanation:

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gavmur [86]

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no it's not.....

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Fine the volume for the shape below: <br><br><br> Please help ASAP, will mark brainlist.
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5 0
3 years ago
I need an answer for part A and B plz
Sladkaya [172]

Answer:

Part A: 4 cups

Part B: 5 fluid ounces

Step-by-step explanation:

Part A: Since the ratio of vinegar to water is 1:16, 1 cup of vinegar is 16 cups of water. Divide both by 4 to get 1/4 cups of vinegar to 4 cups of water.

PartB: Since we have 80 fluid ounces of water, and 16 is 16 times 1, 80/16 is 5 fluid ounces.

6 0
4 years ago
Above are two different models of the same triangular-shaped garden. If the height of the model on the left is 14 cm, what is th
Katyanochek1 [597]

Please consider the attached graph.

We have been given that there are two different models of the same triangular-shaped garden. The height of the model on the left is 14 cm. We are asked to find the height of the model.

First of all, we will convert 14 cm into feet.

We can see that model on left side has a scale of 1 cm is equal to 15 feet.

14 cm = 14×15 feet = 210 feet.

We can see that model on the right side has a scale of 1 cm is equal to 7.5 feet.

Since both models represent same triangular-shaped garden, so the actual height for the both models will be same.

Now we need to convert actual height of 210 feet into inches using 2nd scale.

\text{210 ft}=210\text{ ft}\times \frac{1\text{ inch}}{\text{7.5 ft}}=\frac{210}{7.5}\text{ inch}=28\text{ inch}

Therefore, the height of the model on right is 28 inches.

5 0
4 years ago
A collection of 20 coins made up of only nickels, dimes, and quarters has a total value of $3.35. If the dimes were nickels, the
Kay [80]

Answer:  The required number of quarters in the collection is 11.

Step-by-step explanation:  Given that a collection of 20 coins made up of only nickels, dimes and quarters has a total value of $3.35.

If the dimes were nickels, the nickels were quarters and the quarters were dimes, the collection of coins would have a total value of $2.75.

We are to find the number of quarters in the collection.

Let x, y and z represents the number of nickels, dimes and quarters respectively in the collection.

We will be using the following values of nickels, dimes and quarters in form of dollar :

1 nickel = $ 0.05,   1 dime = $ 0.10   and    1 quarter = $0.25.

Then, according to the given information, we have

x+y+z=20\\\\\Rightarrow x=20-y-z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\0.05x+0.10y+0.25z=3.35\\\\\Rightarrow 5x+10y+25z=335\\\\\Rightarrow x+2y+5z=67~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)\\\\0.05y+0.25x+0.10z=2.75\\\\\Rightarrow 5y+25x+10z=275\\\\\Rightarrow y+2z+5x=55~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iii)

Substituting the value of x from equation (i) in equations (ii) and (iii), we have

(20-y-z)+2y+5z=67\\\\\Rightarrow y+4z=47\\\\\Rightarrow y=47-4z~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(iv)

and

y+2z+5(20-y-z)=55\\\\\Rightarrow -4y-3z=-45\\\\\Rightarrow y=\dfrac{45-3z}{4}~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(v)

Comparing the values of y from equations (iv) and (v), we get

47-4z=\dfrac{45-3z}{4}\\\\\Rightarrow 188-16z=45-3z\\\\\Rightarrow 16z-3z=188-45\\\\\Rightarrow 13z=143\\\\\Rightarrow z=\dfrac{143}{13}\\\\\Rightarrow z=11.

Thus, the required number of quarters in the collection is 11.

7 0
3 years ago
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