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STALIN [3.7K]
3 years ago
12

Write the equation of a line that is perpendicular to y=-x-6y=−x−6y, equals, minus, x, minus, 6 and that passes through the poin

t (-9,-4)(−9,−4)left parenthesis, minus, 9, comma, minus, 4, right parenthesis. PLS HURRY
Mathematics
2 answers:
Anni [7]3 years ago
7 0
The given line has a slope of -1 so the perpendicular line will have a slope of -1/1=1
y=x+5
TEA [102]3 years ago
6 0

Answer:

Step-by-step explanation

Write the equation of a line that is perpendicular to y=-x-6y=−x−6y, equals, minus, x, minus, 6 and that passes through the point (-9,-4)(−9,−4)left parenthesis, minus, 9, comma, minus, 4, right parenthesis.

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Solve the equation using the quadratic formula.<br> 4x2 – 12x +33 = 0
mixer [17]

Answer:

4x2–12x+33=0

Resta 4x  

2

​

 en los dos lados. Cualquier valor restado de cero da como resultado su valor negativo.

−12x+33=−4x  

2

​

 

Resta 33 en los dos lados.

−12x=−4x  

2

​

−33

Divide los dos lados por −12.

−12

−12x

​

=  

−12

−4x  

2

​

−33

​

 

Al dividir por −12, se deshace la multiplicación por −12.

x=  

−12

−4x  

2

​

−33

​

 

Divide −4x  

2

​

−33 por −12.

x=  

3

x  

2

​

 

​

+  

4

11

​

 

Resolver para x_2

x  

2

​

=3x−  

4

33

​

Step-by-step explanation:

8 0
2 years ago
Apiece of paper wieghts 0;647gram what is the wieght of the paper to the nearest tenth of a gram
Svet_ta [14]
0.647 rounded to the nearest tenth = 0.6
7 0
3 years ago
Read 2 more answers
Plz help me my mom and dad don't know this
bezimeni [28]
X/y
x=1 when y= 5
x=2 when y =10
the constant of proportionality = 1/5
7 0
3 years ago
Consider randomly selecting a student at a large university. Let A be the event that the selected student has a Visa card, let B
wariber [46]

Answer:

a. 0.76

b. 0.23

c. 0.5

d. p(B/A) is the probability that given that a student has a visa card, they also have a master card

p(A/B) is the probability that given a student has a master card, they also have a visa card

e. 0.35

f. 0.31

Step-by-step explanation:

a. p(AUBUC)= P(A)+P(B)+P(C)-P(AnB)-P(AnC)-P(BnC)+P(AnBnC)

                    =0.6+0.4+0.2-0.3-0.11-0.1+0.07= 0.76

b. P(AnBnC')= P(AnB)-P(AnBnC)

                    =0.3-0.07= 0.23

c. P(B/A)= P(AnB)/P(A)

             =0.3/O.6= 0.5

e. P((AnB)/C))= P((AnB)nC)/P(C)

                     =P(AnBnC)/P(C)

                     =0.07/0.2= 0.35

f. P((AUB)/C)= P((AUB)nC)/P(C)

                    =(P(AnC) U P(BnC))/P(C)

                     =(0.11+0.1)/0.2

                     =0.21/0.2 = 0.31

7 0
3 years ago
If there are 40 boys and 60 girls in a room, fill out all of the possible ratios of boys to girls that could be made.
galina1969 [7]

40+60=100. So one person equals 1%, meaning 40% are boys and 60% are girls. By simplifying, we will find that possible ratios below the value of 100 are 40:60, 4:6, 2:3, and 20:30.

8 0
3 years ago
Read 2 more answers
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