Answer:
$80
Step-by-step explanation:
First you take 500 and multiply by 16% or .16.
You should get 80.
A tip for the future is when you have a percentage just move the decimal place to the left twice.
ie. 50%=.50, 125%=1.25, 2%=.02
I hope this helps :)
Answer:
very easy 65inches
Step-by-step explanation:
follow me
Answer:
Any set of data that satisfies the 5-Number summary: 1,6,12,16 and 19 can be represented with the box plot.
Step-by-step explanation:
<u>Interpreting Box Plots</u>
A box plot is used to present the 5-Number summary of a set of data.
The 5-Number summary consists of the following in their order of appearance on the box plot.
- Minimum Value
- First Quartile,

- Median,

- Third Quartile,

- Maximum Value
In the box plot, the following rules applies
- The whisker starts from the minimum value and ends at the first quartile.
- The box starts at the first quartile and ends at the third quartile. There is a vertical line inside the box which shows the median.
- The end whisker starts at the third quartile and ends at the maximum value.
Using these, we interpret the given box plot
A left whisker extends from 1 to 6.
- Minimum Value=1
- First Quartile =6
The box extends from 6 to 16 and is divided into 2 parts by a vertical line segment at 12.
- Median=12
- Thrid Quartile=16
The right whisker extends from 16 to 19.
Therefore any set of data that satisfies the 5-Number summary: 1,6,12,16 and 19 can be represented with the box plot.
Answer:
-4
Step-by-step explanation:

Hope this helps!