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Alexxandr [17]
3 years ago
12

Use CALCULUS to find coordinates of the turning point on C.

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
3 0
Oi 

Just calculating the differential. Step by step:

y=12 \sqrt{x} -x \frac{3}{2}-10 \\  \\ y=12x^{ \frac{1}{2} } -x \frac{3}{2}-10 \ \ \ \boxed{transform \  \sqrt{x} =x^{ \frac{1}{2} }}  \\  \\  Differentiating \\  \\ y'=12. \frac{1}{2}.x^{ \frac{1}{2}-1 } -1.x^{1-1}. \frac{3}{2}-0 \\  \\  y'=6.x^{ -\frac{1}{2} } -x^{0}. \frac{3}{2} \\  \\  y'=6. \frac{1}{x^{ \frac{1}{2} }}  -1. \frac{3}{2}  \\  \\  \boxed{y'=\frac{6}{ \sqrt{x} }  -\frac{3}{2}}

If you want to know where the tangent has no slope:

\frac{6}{ \sqrt{x} } - \frac{3}{2} =0 \\  \\  \frac{6}{ \sqrt{x} } = \frac{3}{2}  \\  \\ 3 \sqrt{x} =12 \\  \\  \sqrt{x} = \frac{12}{3}  \\  \\  \sqrt{x} =4 \\  \\   (\sqrt{x})^2 =4^2 \\  \\ x=16
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How do I talk with a live tutoring I took a subscription out ​
posledela

Answer:

what is this question?

Step-by-step explanation:

7 0
3 years ago
How did you get it ?
kakasveta [241]

Answer:get what

Step-by-step explanation:

5 0
3 years ago
Polygon ABCD is reflected and dilated to give polygon PQRS. The coordinates of the preimage are (2, 2), (6, 8), (12, 8), and (16
HACTEHA [7]

Answer: The scale factor of the dilation is 0.5.

Explanation:

It is given that ABCD is polygon which is reflected and dilated , then we get PQRS.

The vertices of ABCD are (2, 2), (6, 8), (12, 8), and (16, 2) respectively. The vertices of image  PQRS are (11, 15),(9, 12), (6, 12), and (4, 15) respectively.

The reflection affects the coordinates but does not affect the length of the sides.

But when we talk about dilation it affects the length of sides according to the scale factor or a constant factor.

If a line segment AB is dilated by scale factor k then length of A'B' is k times length of AB.

|A'B'|=k\times |AB|   .... (1)

So we have to find any side length of preimage and the side length of that side in image. it means we have to find AB and PQ.

Use distance formula to find the side length.

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

AB=\sqrt{(8-2)^2+(6-2)^2}=\sqrt{36+16}=2\sqrt{13}

PQ=\sqrt{(9-11)^2+(12-15)^2}=\sqrt{4+9}=\sqrt{13}

It is noticed that the size of side in preimage is 2\sqrt{13} and the size of same side in image is \sqrt{13}.

Using equation (1), we get

\sqrt{13}=k \times 2\sqrt{13}

k=\frac{1}{2}

k=0.5

Hence, the value of scale factor is 0.5.

7 0
3 years ago
Read 2 more answers
Answer choices:<br>A (3 , -4)<br>B (4 , -7/2)<br>C (-5 , 8)<br>D (5/2 , -17/4)​
zhuklara [117]

Answer: D (5/2, -17/4)

Step-by-step explanation:  Using elimination your goal is to get rid or 1 variable  so you can solve for the one that's left.  By adding the -2y and 2y you will get 0.  You will also add the 3x+x (4x) and -1+11 (10).  You have now gotten rid of the y and have 4x=10.  By dividing each side by 4 we now know x =2.5.  D is the only possible solution with x=2.5 (5/2) but to solve for y you plug 2.5 in to an equation as x so) x-2y=11

                                                                           2.5-2y=11

                                                                            -2y=8.5                                                                        Answer D (5/2,-17/4)                                      y=-17/4 (4.25)

4 0
2 years ago
What statement is true?
givi [52]

Answer:

\frac{18}{32}>\frac{16}{32}

Step-by-step explanation:

We need to find which statements are true.

Solution to find the same we will solve each statement and will conclude the same.

1.  \frac{14}{21}>\frac{17}{24}

Now On solving we get;

\frac{14}{21} = 0.66

\frac{17}{24}=0.70

So we can see that 0.70 > 0.66

Hence The given statement is False.

2. \frac{18}{32}>\frac{16}{32}

Now On solving we get;

\frac{18}{32}=0.5625

\frac{16}{32}= 0.5

So we can see that 0.5625 > 0.5

Hence The given statement is True.

3.  \frac{20}{15}

Now On solving we get;

\frac{20}{15} = 1.33

\frac{28}{23}=1.2

So we can see that 1.33 > 1.2

Hence The given statement is False.

4.  \frac{29}{35}

Now On solving we get;

\frac{29}{35}= 0.82

\frac{20}{30}= 0.66

So we can see that 0.82 > 0.66

Hence The given statement is False.

7 0
3 years ago
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