Part A:<span> What is the mean of the data? Show your work. (4 points)</span>
Part B:<span> Use your answer from Part A to calculate the mean absolute deviation for the data. Show your work. (6 points)
</span>
The table is missing in the question. The table is provided here :
Group 1 Group 2
34.86 64.14 mean
21.99 20.46 standard deviation
7 7 n
Solution :
a). The IV or independent variable = Group 1
The DV or the dependent variable = Group 2
b).
Therefore, 
t = -2.579143
Now, 
df = 7 - 1
= 6
Therefore the value of p :
= 0.020908803
The p value is 0.0209
So we reject the null hypothesis and conclude that 
It would be: - 2 - (-10) = 5x - 12
= -2 + 10 = 5x - 12
= 8 + 12 = 5x
= x = 20 / 5
= x = 4
Answers:Part A: The value of x is 0.Part B: X can be any real number.
In Part A, you have to first evaluate 7^2. This is 49. Now, write the equation 49^x = 1. We know that if you raise any number to 0, then the answer is 1.
In Part B, you have to first evaluate 7^0, that is 1. Now, we have the equation 1^x = 1. In this case, 1 raised to any exponent is still only 1. Imagine 1^17, this would be 1 times itself 17 times or just 1.
Therefore any number will work in Part B.
I believe you meant the equal signs to be division symbols haha. The next step would be 18/6.
