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Leni [432]
3 years ago
13

Which algebraic function has a smaller rate of change than the equation? f(x)=2x−9

Mathematics
1 answer:
vredina [299]3 years ago
4 0
It will be the second option i believe
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45 ( please label me brainliest)

Step-by-step explanation:

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Simplify (x ^2 y)^3. x 2y 3, x 5 y 3, x 6 y 3^
Veronika [31]

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x^6 y^3

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(x ^2 y)^3

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8 0
4 years ago
Given A-<br> 2 2<br> 1 3<br> what is A-¹?
devlian [24]

The inverse of matrix A = \left[\begin{array}{cc}2&2&1&3\\\end{array}\right] is A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|      

The given matrix is A = \left[\begin{array}{cc}2&2&1&3\\\end{array}\right]

The inverse of a matrix is given by

A^{-1} = \frac{1}{|A|} adjA                   ...(1)

Now, determinant of matrix A is

|A| = \left|\begin{array}{cc}2&2&1&3\\\end{array}\right|

= (3)(2) - (2)(1)

= 6 - 2

= 4

Now, adjoint A will be

A_{11} = 3

A_{12} = -1

A_{21} = -2

A_{22} = 2

AdjA = \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|

Now, substituting the values of |A| and AdjA in equation (1), we get

A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|        

Therefore, A^{-1} = \frac{1}{4} \left|\begin{array}{cc}3&-2&-1&2\\\end{array}\right|      

Know more about Inverse of Matrix: -brainly.com/question/12442362

#SPJ9

     

7 0
2 years ago
Which one should I choose
Nostrana [21]

Answer:

its the last one

Step-by-step explanation:

the sign flips when you divide by a negative

6 0
3 years ago
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