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2 years ago

7

a density graph for all the possible weights between 0 pounds and 100 pounds is in the shape of a rectangle. what is the height

of the rectangle in this density curve

1 answer:

Pavel [41]2 years ago

4 0

Answer:

0.1

Step-by-step explanation:

a p e x

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A scale drawing for an apartment shown below in the drawing is 2 cm represent 5m

rjkz [21]

Firstly, found out a square that is 7cm long and 5cm wide, you get the 7 from adding 5+2 across the top. Don't forget that, 2cm = 5m so you get the real area we need to work out how many meters are in each length.

So, firstly you know that in 1 cm there is 2.5m, with this information you can then do 7x2.5 to get the distance across the top in meters. That gives you 17.5 megers for the top and 5x2.5 = 12.5m.

After finding that, you have to find the area of this square, so you do 17.5m x 12.5m = 218.75m^2 for the biggest square, that's the total area however we want the bedroom area.

Therefore we have to workout how much area is in the living room and take that away from the total amount. Since we found out how many meters are in the 5cm we can use that here again. 12.5m x 12.5m = 156.25m^2 with this we do 218.75m^2 - 156.25m^2 = 62.5m^2 is for the bedroom and small empty space. now we just need to find the small empty space.

To do that, we do 5-4 which leave us with 1 cm and we already know it's across length is 2, with the information provided and stated we know that it's 2.5m x 5m = 12.5m^2

Then finally we do 62.5m^2 - 12.5m^2 to get the bedroom area. <u>50m^2</u>

6 0

2 years ago

One number is 3/8 of another number. The difference of the two numbers is 4.2. What is the lesser number

boyakko [2]

Answer:

2.52.

Step-by-step explanation:

If one number is x then the other = 3x/8.

Also x - 3x / 8 = 4.2

x - 0.375 x = 4.2

0.625x = 4.2

x = 4.2 / 0.625

x = 6.72.

So the lesser number is 6.72 * 0.375 = 2.52.

4 0

2 years ago

Consider the two data sets below:

alina1380 [7]

Answer:

<u><em>Option c) The data sets will have the same values of their interquartile range.</em></u>

<u><em></em></u>

Explanation:

<u>1. The values are in order: </u>they are in increasing oder, from lowest to highest value.

<u>2. Calculate the interquartile range.</u>

<em />

<em>Interquartile range</em>, IQR, is the third quartile, Q3, less the first quartile Q1:

IQR = Q3 - Q1

To find the first and the third quartile, first find the median:

<u>Data Set 1</u>: 19, 25, 35, 38, 41, 49, 50, 52, 59

[19, 25, 35, 38], 41, [49, 50, 52, 59]

↑

median = 41

<u>Data Set 2</u>: 19, 25, 35, 38, 41, 49, 50, 52, 99

[19, 25, 35, 38] , 41, [49, 50, 52, 99]

↑

median = 41

Now find the median of each subset: the values below the median and the values above the median.

Data set 1: <u>First quartile</u>

[19, 25, 35, 38],

↑

Q1 = [25 + 35] / 2 = 30

<u>Third quartile</u>

[49, 50, 52, 59]

↑

Q3 = [50 + 52] / 2 = 51

IQR = Q3 - Q1 = 51 - 30 = 21

Data set 2: <u> First quartile</u>

[19, 25, 35, 38]

↑

Q1 = [25 + 35] / 2= 30

<u>Third quartile</u>

[49, 50, 52, 99]

↑

Q3 = [52 + 50]/2 = 51

IQR = 51 - 30 = 21

Thus, it is shown that the data sets have will have the same values for the interquartile range: IQR = 21. (option c)

This happens because replacing one extreme value (in this case the maximum value) by other extreme value does not affect the median.

<em>An outlier will change the range</em> because the range is the maximum value less the minimum value.

5 0

2 years ago

Find the Area of this figure.

grin007 [14]

Answer:

158 m²

Step-by-step explanation:

I made this into 3 rectangles.

Figure 1:

9•8=72

The 9 is from the 13 m side, but I've taken 4 m off from the overlapping square.

Figure 2:

6•7=42

The 7 is from the 10 m side, but I've taken 4m off from the overlapping square again.

Remaining Area:

If you extend the lines into figures 1 and 2 from the top left corner and bottom right corner vertically, you will get a rectangle that is (11 m) x (4 m). This is not yet accounted for.

11•4=44

Add together: 72 + 42 + 44 = <u>158</u>

*Note: You could also find the area of the squares a much easier way by subtracting the overlapping part after finding the area of both figures , but this is how I did it*

5 0

2 years ago

Can someone help me with these ?

Komok [63]

Triangle
Hexagon
Octagon
Quadrilateral

6 0

2 years ago