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3 years ago

The answer to number b.

Mathematics

2 answers:

natka813 [3]3 years ago

7 0

Her time spent walking was 108 minutes which is 45%

mamaluj [8]3 years ago

6 0

She spent 108 minutes walking last week. 45% of 240 is 108.

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HELPPPPPPPP NOWWWW! WILL MARK BRAINLIESTTTTT!

OLEGan [10]

1. slope of the given line = 1/5
the equation is
(y-2)/(x-(-2))=1/5
x+2=5y-10
x-5y+12=0

2. slope of the given line = -1/6
the equation is
(y-9)/x=6
y-9=6x
y=6x+9

5 0

2 years ago

a biker travel 5ft in .05seconds. At that same rate of speed , how far will the biker travel in 1minute?

Solnce55 [7]

Biker's rate is:

v = 5/0.5

v = 10 ft per sec

t = 1 min = 60 sec

d = the distance the biker travels in 1 minute

v = d/t

d = v*t

d = 10*60

d = 600 ft

The biker travels 600 feet in 1 minute

5 0

3 years ago

What is the volume of this cone?

ki77a [65]

Answer:

r=6.1cm

volume=1/3πr^2

=1/3×22/7×6.1^2

=818.62/21

=38.98cm^3

5 0

2 years ago

Write me What is 10/12 using simplest form

Serjik [45]

Found it online hope that’s helps

8 0

2 years ago

Read 2 more answers

Use technology or a z-score table to answer the question.

Alik [6]

Answer:

The second choice: Approximately $65.2\%$ of the pretzel bags here will contain between 225 and 245 pretzels.

Step-by-step explanation:

This explanation uses a z-score table where each $z$ entry has two decimal places.

Let $\mu$ represent the mean of a normal distribution of variable $X$ . Let $\sigma$ be the standard deviation of the distribution. The z-score for the observation $x$ would be:

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question,

$\mu = 240$ .
$\sigma = 9.3$ .

Calculate the z-score for $x_1 = 225$ and $x_2 = 245$ . Keep in mind that each entry in the z-score table here has two decimal places. Hence, round the results below so that each contains at least two decimal places.

$\begin{aligned} z_1 &= \frac{x_1 - \mu}{\sigma} \\ &= \frac{225 - 240}{9.3} \approx -1.61\end{aligned}$ .

$\begin{aligned} z_2 &= \frac{x_2 - \mu}{\sigma} \\ &= \frac{245 - 240}{9.3} \approx 0.54\end{aligned}$ .

The question is asking for the probability $P(225 \le X \le 245)$ (where $X$ is between two values.) In this case, that's the same as $P(-1.61 \le Z \le 0.54)$ .

Keep in mind that the probabilities on many z-table correspond to probability of $P(Z \le z)$ (where $Z$ is no greater than one value.) Therefore, apply the identity $P(z_1 \le Z \le z_2) = P(Z \le z_2) - P(Z \le z_1)$ to rewrite $P(-1.61 \le Z \le 0.54)$ as the difference between two probabilities:

$P(-1.61 \le Z \le 0.54) = P(Z \le 0.54) - P(Z \le -1.61)$ .

Look up the z-table for $P(Z \le 0.54)$ and $P(Z \le -1.61)$ :

$P(Z \le 0.54)\approx 0.70540$ .
$P(Z \le -1.61) \approx 0.05370$ .

$\begin{aligned}& P(225 \le X \le 245) \\ &= P\left(\frac{225 - 240}{9.3} \le Z \le \frac{245 - 240}{9.3}\right)\\&\approx P(-1.61 \le Z \le 0.54) \\ &= P(Z \le 0.54) - P(Z \le -1.61)\\ &\approx 0.70540 - 0.05370 \\& \approx 0.65.2 \\ &= 65.2\% \end{aligned}$ .

3 0

3 years ago