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4 years ago

A rectangular picture frame measures 27 cm by 48 cm. What is the perimeter or distance around the picture frame in meters

Mathematics

1 answer:

Firlakuza [10]4 years ago

7 0

150, you just add the numbers

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How do you write two hundred fifty-two and thirty-one ten thousandths

ryzh [129]

Answer:

252.3110

Step-by-step explanation:

5 0

3 years ago

EASY MATH!!! GIVING BRAINLIEST!!

musickatia [10]

Answer:

Step-by-step explanation:

So lets take our 50 dollars.

Next, take your increase of 5%. Remember, 5% is 0.05, and it is a increase of 5%, so we are multipling 50 by 1.05.

Before we start multiplying, lets recall that this occurs twice(2 years), but this doesnt mean we multiply 50 by 1.10. No, we just mutiply 50 by 1.05 2 times:

50*1.05

52.5

52.5*1.05

55.25

So your answer is 55 dollars(rounding down).

Hope this helps!

4 0

3 years ago

Which expression is equivalent to 30°?

Zarrin [17]

Answer:

221.671683 grsde

Step-by-step explanation:

4 0

3 years ago

Classify the graph of the functions as linear and non-linear.

olganol [36]

Linear graphs:

1, 4, and 6

Non-linear graphs:

2, 3, and 5

Explanation:

Linear graphs are straight line, non-linear graphs are not straight lines.

3 0

3 years ago

Consider a system with one component that is subject to failure, and suppose that we have 115 copies of the component. Suppose f

castortr0y [4]

Answer:

Step-by-step explanation:

From the given information:

the mean $(\mu) = 115 \times 20$

= 2300

Standard deviation = $20 \times \sqrt{115}$

Standard deviation (SD) = 214.4761

TO find:

a) $P(x > 3500)= P(Z > \dfrac{3500-\mu}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{3500-2300}{214.4761})$

$P(x > 3500)= P(Z > \dfrac{1200}{214.4761})$

$P(x > 3500)= P(Z >5.595)$

From the Z-table, since 5.595 is > 3.999

$P(x > 3500)=1-0.9999$

P(x > 3500) = 0.0001

Here, the replacement time for the mean $(\mu) = \dfrac{0+0.5}{2}$

= 0.25

Replacement time for the Standard deviation $\sigma = \dfrac{0.5-0}{\sqrt{12}}$

$\sigma = 0.1443$

For 115 component, the mean time = (115 × 20)+(114×0.25)

= 2300 + 28.5

= 2328.5

Standard deviation = $\sqrt{(115\times 20^2) +(114\times (0.1443)^2)}$

= $\sqrt{(115\times 400) +(114\times 0.02082249}$

= $\sqrt{(46000) +2.37376386}$

= $\sqrt{(46000) +(2.37376386)}$

= $\sqrt{46002.374}$

= 214.482

Now; the required probability:

$P(x > 4125) = P(Z > \dfrac{4125- 2328.5}{214.482})$

$P(x > 4125) = P(Z > \dfrac{1796.5}{214.482})$

$P(x > 4125) = P(Z >8.376)$

$P(x > 4125) =1- P(Z$

From the Z-table, since 8.376 is > 3.999

P(x > 4125) = 1 - 0.9999

P(x > 4125) = 0.0001

7 0

3 years ago