All categories

3 years ago

What is the common point between lines y = ½ x + 4 and y = x – 4?

Mathematics

1 answer:

nirvana33 [79]3 years ago

7 0

1/2X+4=X-4
1/2X+8=X
8=1/2X
16=X

(Pick one of the equations )
y=1/2X+4
y=(1/2)(16)+4
y=12

point: (16,12)

You might be interested in

What is the ratio of the sides of triangle XYZ?<br> --> can anyone solve this equation ?

lubasha [3.4K]

Answer:

1:2:√3

Step-by-step explanation:

since XYZ is a special right triangle

8 0

3 years ago

What is the answer to this56÷98

Snezhnost [94]

It will be a funny fraction = 0.5714285714

3 0

3 years ago

Read 2 more answers

This is a Differential Equations problem, I only need help on part 1 from question five. I need steps as well, thank you.

jolli1 [7]

Answer:

a) $y(t) = \sqrt{2t + 1 }$

b) 1.5 hours after thickness will be 2 inches.

Step-by-step explanation:

$\frac{dy}{dt} = \frac{1}{y} \\ \\ ydy = dt \\ \\ integrating \: both \: sides \\ \\ \int y \: dy = \int 1 \: dt \\ \\ \frac{ {y}^{2} }{2} = t + c \\ \\ {y}^{2} = 2t + 2c \\ \\ y (t)= \sqrt{2t + 2c} ...(1) \\ \\ a) \: \: \: plug \: t = 0 \: in \: (1) \\ \\ y (0)= \sqrt{2(0) +2 c} \\ \\ y (0)= \sqrt{0 +2 c} \\ \\ 1 = \sqrt{2c} \: \: ( \because \: y (0)=1) \\ \\ 2c = 1 \: \implies \: c = \frac{1}{2} \\ \\ plug \: c = \frac{1}{2} \: in \: (1) \\ \\ y(t) = \sqrt{2t + 2 \times \frac{1}{2} } \\ \\ \huge \: \red {y(t) = \sqrt{2t + 1 } } \\ \\b) \: \: plug \: y(t) = 2 \: in \: above \: equation \\ \\ 2 = \sqrt{2t + 1} \\ \\ 4 = 2t + 1 \: \\ (squaring \: both \: sides) \\ \\ 4 - 1 = 2t \\ \\ 2t = 3 \\ \\ t = \frac{3}{2} \\ \\ t = 1.5 \: hours \\$

6 0

2 years ago

Write a paragraph proof.

worty [1.4K]

It is given that line segment BC is congruent to line segment EC and that line segment AC is congruent to DC. Because of the vertical angles theorem, angle BCA is equal to angle DCE. Therefore, triangles CBA AND DEC are congruent by SAS. Using CPCTC, BA is equal to ED.

8 0

3 years ago

QRST is a parallelogram. Find x and y.

Wewaii [24]

In parallelograms, opposite sides are congruent, meaning that they are the same lengths. So, we have:

y - 4x = 9

-x + 4 = y

Add x to both sides of the second equation:

y + x = 4

y - 4x = 9

This is a system of linear equations. Solve by eliminating the y and subtracting the two equations:

5x = -5

x = -1

Use x to solve for y:

y + (-1) = 4

y = 5

So, x = -1 and y = 5.

5 0

3 years ago