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3 years ago

You need £2,500 as a deposit for a new car. You have already saved 50% of this amount.

Mathematics

1 answer:

Hatshy [7]3 years ago

5 0

1/4 of 2,500 i hope you get it right

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Decimal work 4.5 divided by 0.56 (brainliest if you get it right)

fredd [130]

Answer:

8.03 or 8.035714 and some other numbers that i cant bother to write out. also as a fraction it would be 803/100

7 0

3 years ago

Read 2 more answers

I Really Need Help!!!!! :)

DerKrebs [107]

Answer:

Hence first graph is the correct answer.

T I

1 28

2 56

3 84

4 112

Step-by-step explanation:

Given that initial amount P = $400

Simple rate of interest = R = 7% = 0.07

Time t= 1,2,3,4 years.

Then apply Simple interest formula to find the total interest earned in the given years.

I=PRT

for t=1 year

I=PRT=400(0.07)(1)=28

for t=2 year

I=PRT=400(0.07)(2)=56

for t=3 year

I=PRT=400(0.07)(31)=84

for t=4 year

I=PRT=400(0.07)(4)=112

Now we have table as shown below:

T I

1 28

2 56

3 84

4 112

Graphing these points we see that obtained graph best matches with First choice .

Hence first graph is the correct answer.

7 0

3 years ago

Please answer immediately

Readme [11.4K]

Answer:

c...................

8 0

3 years ago

Read 2 more answers

I need help I need help

Cerrena [4.2K]

Answer:

${ \boxed{ \bf{c}}} \: \: \frac{3.8}{4} = s$

Step-by-step explanation:

${ \tt{4 \: pies \: = \: 3.8 \: ounces}} \\ { \tt{1 \: pie \: = \: ( \frac{1}{4} \times 3.8) \: ounces}} \\ { \tt{ = 0.95 \: ounces}}$

${ \underline{ \sf{ \blue{christ \: † \: alone}}}}$

5 0

3 years ago

A person gets on and off a bathroom scale four times. The four readings (in pounds) are 148, 151, 150, and 152. Each time after

Ganezh [65]

Answer:

See explanation below

Step-by-step explanation:

Since each time after the person gets off the scale, the reading is 2 lb the person's weight must be near the mean of

148-2, 151-2, 150-2, 152-2; that is to say, near the mean of 146, 149, 148, 150 = (146+149+148+150)/4 = 148.25

We could estimate the uncertainty as the standard error SE

$\bf SE=\frac{s}{\sqrt{n}}$

where

s = standard deviation of the sample

n = 4 sample size.

Computing s:

$\bf s=\sqrt{\frac{(146-148.25)^2+(149-148.25)^2+(148-148.25)^2+(150-148.25)^2}{4}}=1.479$

So, the uncertainty is 1.479/2 = 0.736

It is not possible to estimate the bias, since it is the difference between the true weight and the mean, but we do not know the true weight.

5 0

3 years ago