1. 3n
2. 9x
3. 9wx
4. 5ac^2
5. 8wx^2
6. 4a^2 c
Given:
x lies in the III quadrant.
To find:
The values of .
Solution:
It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.
We know that,
x lies in the III quadrant. So,
Now,
And,
We know that,
Therefore, the required values are .
Answer:
Step-by-step explanation:
given,
a) √x + 6 = 4
to solve the above equation subtract both side with 6
√x + 6 - 6 = 4 - 6
√x = -2
squaring both side
(√x)² = (-2)²
x = 4
a) ∛x + 6 = 4
to solve the above equation subtract both side with 6
∛x + 6 - 6 = 4 - 6
∛x = -2
cubing both side
(√x)³ = (-2)³
x = -8
Replace all values of x as 4
f(4)=1/2(4)+5
f(4)=4/2+5
f(4)=2+5
f(4)=7
Hope I helped :)