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Alex17521 [72]
3 years ago
9

Hello please could you answer the questions in the attachment about arc length and the area of a sector. Please show full workin

g out.
(note I have provided 2 attachments both of the same sheet in case 1 isn't clear)

Thanks :)

Mathematics
2 answers:
scoundrel [369]3 years ago
4 0
Easy peasy
so remember that
1 ful roation=360 degrees
so
if you are given an arc of x degrees, that arc's area=x/360 of total area and the arc legnth=x/360 of circumference so

1. a. 60/360 times 10 times 2 times pi=(10pi)/3 cm
b. 60/360 times 10^2 times pi=(50pi)/3 cm^2

2. a. 120/360 times 5 times 2 times pi=(10pi)/3 cm
b. 120/360 times 5^2  times pi=(25pi)/3 cm^2

3.a. 45/360 times 2 times 2.4 times pi=0.6pi cm
 b. 1/8 times 2.4^2 times pi=0.72pi cm^2

4.a. 75/360 times 3.2 times 2 times pi=(4pi)/3 cm
b. (40.96pi)/3 cm^2

5.a.150/360 times 2 times 72 times pi=2pi cm
b.  72pi cm^2

6.a. 15/360 times 2 times 12 times pi=pi cm
b. 6pi cm^2

7.a. quarter is 1/4 so 1/4 2 pi 1.9=0.95pi cm
b. 0.9025pi cm^2
ipn [44]3 years ago
4 0
Don't worry I print out your sample and do the working and give you the full solutions with another sample.......Is it an assignment by the way so I can know that you're not rushing or otherwise I can know do it fastly


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4 years ago
60 is 15% of what number?
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Method 1

\begin{array}{ccc}60&-&15\%\\x&-&100\%\end{array}\ \ \ \ |cross\ multiply\\\\15x=60\cdot100\\15x=6000\ \ \ \ \ |divide\ both\ sides\ by\ 15\\\boxed{x=400}

Method 2

\begin{array}{cccc}15\%&-&60&|divide\ both\ sides\ by\ 3\\\\5\%&-&20&|multiply\ both\ sides\ by\ 20\\\\100\%&-&400\end{array}

Method 3

p\%=\dfrac{p}{100}\\\\15\%=\dfrac{15}{100}=0.15\\\\0.15x=60\ \ \ \ |divide\ both\ sides\ by\ 0.15\\x=400
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