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never [62]
3 years ago
13

A new seven-story apartment building is opening in our town. i was curious when i read that the apartments on the higher floors

were more expensive, so i went to the open house. i discovered that there is only one very large apartment on the top floor. each floor has twice as many apartments as the floor above it. the lowest floor contains only one-room studio apartments that are very small. how many apartments are in this new building?
Mathematics
1 answer:
mina [271]3 years ago
3 0
1+2+4+8+16+32+64=127 apartments
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Math is annoying! Can someone help me please?
lord [1]
16.  would be C since they both consist of the same variable to the same power

17. x-2x+7-9+4x
     c. 3x-2
18. -4(3a-5). You would multiply -4 by 3 a, and -4 by -5. It turns to
      -4(3a)-4(-5)
     a. -12a+20
4 0
3 years ago
What is the maximum volume in cubic inches of an open box to be made from a 12-inch by 16-inch piece of cardboard by cutting out
Romashka-Z-Leto [24]

If you start with a 12x16 rectangle and cut square with side length x, when you bend the sides you'll have an inner rectangle with sides 12-2x and 16-2x, and a height of x.

So, the volume will be given by the product of the dimensions, i.e.

(12-2x)(16-2x)x = 4x^3-56x^2+192x

The derivative of this function is

12x^2-112x+192

and it equals zero if and only if

12x^2-112x+192=0 \iff x = \dfrac{14\pm 2\sqrt{13}}{3}

If we evaluate the volume function at these points, we have

f\left(\dfrac{14-2\sqrt{13}}{3}\right) = \dfrac{64}{27}(35+13\sqrt{13})> f\left(\dfrac{14-2\sqrt{13}}{3}\right) = -\dfrac{64}{27}(13\sqrt{13}-35)

So, the maximum volume is given if you cut a square with side length

x=\dfrac{14-2\sqrt{13}}{3}\approx 2.7

5 0
3 years ago
(7y – 20)<br> (5х – 38)<br> (3х – 4)<br> -<br> m
egoroff_w [7]

Answer:

um

Step-by-step explanation:

8 0
2 years ago
Can you help me with this problem please
Over [174]

Remark

I think you want us to do both 3 and 4


Three

QR is 4 points going left from the y axis + 2 points going right from the y axis.

QR = 6 units long.


RT is 4 units above the x axis and 3 units below the x axis

RT = 7 units long


TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.


Problem 4

You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.


Area = (b1 + b2)*h/2


Givens

B1 = QR = 6

B2 = UT + TS = 6 + 3 = 9

h = RT = 7


Area

Area = (6 + 9)*7/2

Area = 15 * 7 / 2

Area = 52.5


Comment

You could break this up into a rectangle + a triangle

Find the area of QRTU and add the Area of triangle RTS


<em>Area of the rectangle </em>= L * W

L = RT = 7

W = QR = 6

Area = 7 *6 = 42


<em>Area of the triangle</em> = 1/2 * B * H

B = TS = 3

H = RT =7

Area = 1/2 * 3 * 7

Area = 1/2 * 21

Area = 10.5


Total Area = 42 + 10.5 = 52.5 Both answers agree.

3 0
3 years ago
Suppose the domain of g is ( negative infinity, infinity). Is the domain of f o g ( negative infinity, infinity)?
Anna007 [38]
The domain and range of the composition of f of g is not necessarily equal to the domain and range of g since the function f . This will only be true if the domain and range of the function f is (negative infinity, infinity).<span />
8 0
3 years ago
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