Answer:
The rate of decrease is: 
Step-by-step explanation:
Given
---- We used minus because the rate is decreasing
Required
Rate of decrease when:
The volume of the cube is:
Differentiate
Make dV the subject
Divide both sides by dt
Given that: and
<em>Hence, the rate of decrease is: 43.2mm^3/min</em>
the ratio is 24:30
or the simplified version is 4:5
Did you ever get the answer to this?:
Step-by-step explanation:
The equation has the same solution as w / 3.9 = 3 is w+0.6=1.9
Given:
w / 3.9 = 3
cross multiply
w × 3 = 3.9
3w = 3.9
divide both sides by 3
w = 3.9 / 3
w = 1.3
<em>Check all that applies</em>
A. w+0.6=1.9
w = 1.9 - 0.6
w = 1.3
B. w-0.6 = 11.1
w = 11.1 + 0.6
w = 11.7
C. w+1.03=2.93
w = 2.93 - 1.03
w = 1.9
D. w-1.03=8.24
w = 8.24 + 1.03
w = 9.27
Therefore, the equation has the same solution as w / 3.9 = 3 is w+0.6=1.9
Learn more about equation:
brainly.com/question/2972832
Answer:
0.35m + 25 = 42.50
Step-by-step explanation:
If you were to rent a truck for one day you will first have to pay a $25 fee for one day. This is represented by + 25 in the equation above.
Then for every mile you go you must pay $0.35, represented as 0.35m.
<em>As an example to make it easier if you had to pay 1 dollar per mile and you went 10 miles it would cost $10. This can be proved by 1m (m being the variable for number of miles) Plug in 10 for m and you can asee 1(10)=10, because obviously 1 times 10 is 10. </em>
Same premise with $0.35
Then both of those fees added up are equal to a total of $42.50.
To prove it can find the exact number of miles that need to be driven to cost a total of $42.50 just follow steps bellow.
1. 0.35m + 25 - 25 = 42.50 - 25
Subtracting the inital fee since it is part of the total, and if you add/subtract/multiply/divide on one side you must do to the other.
2. 0.35m/0.35 = 17.50/0.35
You divide because m is being multiplied with 0.35 and to undo the multiplication you divide. Doing the same to both sides.
3. m = 50
Plug in 50 to "m" in the equation above and if both sides are equal the answer is valid.
