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Arisa [49]
3 years ago
10

Twice the sum of a number and 3 is 20.

Mathematics
2 answers:
tamaranim1 [39]3 years ago
4 0

Answer:

true

Step-by-step explanation:

Nastasia [14]3 years ago
4 0
This is very true
Lol
Oof
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Hello - I have one last question that I think you might be able to help me with. Thanks~
Nata [24]
Let slant height be s
Height = 38yd. = h
Side = 42yd. = a

S² = h² + (a/2)²
= 38² + 21²
= 1444 + 441
= 1885
S = √1885
S = 43.42yd.

Lateral area = 1/2 × 4a × s
= 2 × 42 × 43.42
= 3646.99
= 3647 yd.²
7 0
3 years ago
Read 2 more answers
Molly uses 9.5 pints of blue paint and white paint to paint her bedroom walls. 3 4 of this amount is blue paint, and the rest is
Vilka [71]

Answer:

  2.375 pints

Step-by-step explanation:

Since 3/4 of the paint is blue, the remaining 1/4 of the paint is white. 1/4 of the total amount is ...

  (1/4)(9.5 pints) = 2.375 pints . . . . of white paint

5 0
3 years ago
Please help! <br><br> ~I WILL MARK BRAINLIEST!~
likoan [24]
I’m pretty sure it is B
Hope I helped.
6 0
3 years ago
Read 2 more answers
The bottom of Ignacio's desktop is 74.5cm from the floor. Ignacio's sits in his adjustable chair, and the tops of his legs are 4
dsp73

Answer:

Ignacio can make 5 clockwise rotations.

Step-by-step explanation:

Given that the Ignacio's legs are already at a height of 49.3cm and each rotation of the chair knob raises his legs another 4.8cm, we can set up an inequality to determine the number of rotations Ignacio could make without his legs touching the desk, which is at a height of 74.5cm:

4.8r + 49.3 < 74.5  where 'r' is equal to the number of rotations

The sum of the Ignacio's original leg height plus the amount of height increased from the rotations of the know must be less than 74.5 in order for his legs not to touch.  Now, solve for 'r':

Subtract 49.3 from both sides:  4.8r + 49.3 - 49.3 < 74.5 - 49.3 or 4.8r < 25.2

Divide 4.8 from both sides:  4.8r/4.8 < 25.2/4.8 or  r < 5.25

Since the number of rotations must be less than 5.25, he can make 5 complete rotations.  

6 0
3 years ago
In ΔABC, AD and BE are the angle bisectors of ∠A and ∠B and DE║ AB. Find the measures of the angles of ΔABC, if m∠ADE: m∠ADB = 2
drek231 [11]

Answer:   ∠A=48°,∠B=48°,∠C=84°.


Step by-step explanation:

Given:  AD and BE are the angle bisectors  of ∠A and ∠B

i.e ∠6=∠7    ( ∵ Angles formed after  AD bisected ∠A)

∠4=∠5       ( ∵ Angles formed after  BE bisected ∠B)

Also,  DE║AB

⇒ ∠2=∠7   (∵ Alternate interior angles)

   ∠3=∠6   (∵ Alternate interior angles)

And ∠ADE : ∠ADB =∠2:∠3= 2:9 =2x : 9x     ..(1)

To Find:  ∠A,∠B,∠C.

Solution:  ∠2=∠7 (∵ Given)    ...(2)

∠2=∠4  (∵ angles on the same segment)    ...(3)

∠4=∠5 =∠B/2 (∵ Given)    ...(4)

∴ In Δ ABD

∠3+∠4+∠5+∠7 = 180 (∵ Sum of interior angles of a triangle)

From equation 2,3,4,5, Put values

9x+2x+2x+2x =180°

⇒15x = 180°

⇒x=12°

Putting values in equation (4) ⇒ ∠ B =2*(2*12) = 48°

Also, <u>∠B=∠A=48°</u>

Now,in Δ ABC

∠C+∠B+∠A= 180°

⇒48°+48°+∠C= 180°

<u><em>⇒∠C=84°</em></u>

6 0
3 years ago
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