2 radians = 2 full rotations
pi = 3.14
circumference of wheel = 2(pi)r
= 20 * 3.14
=62.8 cm
= 0.628m
meters rolled = 0.628 * 2
=1.256 m
Let
x-------> the number of dinner
y-------> the number of lunch
we know that
-------> equation A
------> equation B
Substitute equation B in equation A
![8[y]+5y \leq 42](https://tex.z-dn.net/?f=8%5By%5D%2B5y%20%5Cleq%2042)



so
the greatest number of lunch is 

Hence
the greatest number of dinner is 
therefore
the greatest number of meals is

<u>the answer is</u>

Answer: 0.94
Step-by-step explanation:
Hello there. I did one part of your question.
4x + 2y + z = 8
<span><span>−<span>4x</span></span>−<span>2y</span></span>+<span>8</span>
Answer:
a. (6x-5)^2
b. 4x(2x^2+1)
c. -4(x-12)(x+3)
d. (2x+1)(4x-3)
Step-by-step explanation: