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Pani-rosa [81]
3 years ago
9

What is the coefficient of the expression: 3n+4

Mathematics
2 answers:
Mice21 [21]3 years ago
7 0

Answer:

3

Step-by-step explanation:

umka2103 [35]3 years ago
4 0

Answer:

The coefficient is 3, the number right before the variable.

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Galina-37 [17]

Answer: 25.12

Step-by-step explanation: good luck

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2 years ago
Which ordered pair could be removed to
Kobotan [32]

Answer:

The answer is choices D.

Step-by-step explanation:

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3 years ago
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The popualtion in 2016 is 899 447, the population increases by 8.1% in three years
il63 [147K]

Answer:

8.1% of 899,447 = 72855.20700000001

4 0
3 years ago
wo point charges lie on the $x$ axis. A charge of +6.24 $\mu C$ is at the origin, and a charge of -9.55 $\mu C$ is at $x$ = 12.0
Andreyy89

Answer:

E_n=34,467,075.42\ N/C

Step-by-step explanation:

<u>Electric Field</u>

The electric field produced by a point charge Q at a distance d is given by

\displaystyle E=K\cdot \frac{Q}{d^2}

Where

K = 9\cdot 10^9\ Nw.m^2/c^2

The net electric field is the vector addition of the individual electric fields produced by each charge. The direction is given by the rule: If the charge is positive, the electric field points outward, if negative, it points inward.

Let's calculate the electric fields of each charge at the given point. The first charge q_1=+6.24\mu C=6.24\cdot 10^{-6}C is at the origin. We'll calculate its electric field at the point x=-3.85 cm. The distance between the charge and the point is d=3.85 cm = 0.0385 m, and the electric field points to the left:

\displaystyle E_1=9\cdot 10^9\cdot \frac{6.24\cdot 10^{-6}}{0.0385^2}

E_1=37,888,345.42\ N/C

Similarly, for q_2=-9.55\mu C=-9.55\cdot 10^{-6}C, the distance to the point is 12 cm + 3.85 cm = 15.85 cm = 0.1585 m. The electric field points to the right:

\displaystyle E_2=9\cdot 10^9\cdot \frac{9.55\cdot 10^{-6}}{0.1585^2}

E_2=3,421,270\ N/C

Since E1 and E2 are opposite, the net field is the subtraction of both

E_n=37,888,345.42\ N/C-3,421,270\ N/C

\boxed{E_n=34,467,075.42\ N/C}

6 0
3 years ago
The following show a change of scale made by an architect in one of his drawings.Old: 1 in. =16 cm. New:1in. =2cm Which is the c
Varvara68 [4.7K]
The scale factor changes by 1/8.

The numerator, 1 stays the same; the denominator changes. 16/2 = 8; it is 1/8 the scale of the previous scale.
8 0
3 years ago
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