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3 years ago

What is 8sin(8x)+9=3

Mathematics

1 answer:

Archy [21]3 years ago

6 0

Answer:

i = -0.09375n-1s-1x-1

Step-by-step explanation:

Simplifying

8sin(8x) + 9 = 3

Remove parenthesis around (8x)

8ins * 8x + 9 = 3

Reorder the terms for easier multiplication:

8 * 8ins * x + 9 = 3

Multiply 8 * 8

64ins * x + 9 = 3

Multiply ins * x

64insx + 9 = 3

Reorder the terms:

9 + 64insx = 3

Solving

9 + 64insx = 3

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-9' to each side of the equation.

9 + -9 + 64insx = 3 + -9

Combine like terms: 9 + -9 = 0

0 + 64insx = 3 + -9

64insx = 3 + -9

Combine like terms: 3 + -9 = -6

64insx = -6

Divide each side by '64nsx'.

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Evaluate the expression for u = 5

baherus [9]

Answer:

Step-by-step explanation: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

u-(5)=0

Step by step solution :

STEP

Solving a Single Variable Equation:

1.1 Solve : u-5 = 0

Add 5 to both sides of the equation :

u = 5

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3 years ago

Matrices A and B are square matrices of the same size. Prove Tr(c(A + B)) = C (Tr(A) + Tr(B)).

alexira [117]

Answer with Step-by-step explanation:

We are given that two matrices A and B are square matrices of the same size.

We have to prove that

Tr(C(A+B)=C(Tr(A)+Tr(B))

Where C is constant

We know that tr A=Sum of diagonal elements of A

Therefore,

Tr(A)=Sum of diagonal elements of A

Tr(B)=Sum of diagonal elements of B

C(Tr(A))= $C\cdot$ Sum of diagonal elements of A

C(Tr(B))= $C\cdot$ Sum of diagonal elements of B

$C(A+B)=C\cdot (A+B)$

Tr(C(A+B)=Sum of diagonal elements of (C(A+B))

Suppose ,A= $\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]$

B= $\left[\begin{array}{ccc}1&1\\1&1\end{array}\right]$

Tr(A)=1+1=2

Tr(B)=1+1=2

C(Tr(A)+Tr(B))=C(2+2)=4C

A+B= $\left[\begin{array}{ccc}1&0\\1&1\end{array}\right]+\left[\begin{array}{ccc}1&1\\1&1\end{array}\right]$

A+B= $\left[\begin{array}{ccc}2&1\\2&2\end{array}\right]$

C(A+B)= $\left[\begin{array}{ccc}2C&C\\2C&2C\end{array}\right]$

Tr(C(A+B))=2C+2C=4C

Hence, Tr(C(A+B)=C(Tr(A)+Tr(B))

Hence, proved.

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DerKrebs [107]

Answer:

Step-by-step explanation:

The scale factor is 5. Answered by Gauthmath

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3 years ago

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GenaCL600 [577]

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3 years ago

Help please!! :-(<br> x = -5<br><br> -x + 8

Anna [14]

Answer:

Step-by-step explanation:

-(-5) + 8

5 + 8

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3 years ago

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