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2 years ago

Please help with this

Mathematics

1 answer:

babunello [35]2 years ago

6 0

Answer: Circle lines

Step-by-step explanation:

Hopefully the attached image helps, it is a diagram of all the labeled lines on a circle excluding the radius (BG or GE)

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What is the solution the solution to x/-1 > -6

wlad13 [49]

Answer:

x < 6

Step-by-step explanation:

x/-1 > -6

x < (-6) * (-1)

so, x < 6

5 0

3 years ago

The khans car averages 22 miles per gallon of gas predict how far can thay travel on 5 gallons of gas

kodGreya [7K]

If the Khans car runs 22 miles per one gallon, then on 5 gallons of gas they can drive 110 miles.

1 gallon = 22 miles

5g x 22m = 110

I hope this helps! If I did something wrong, please correct me!

5 0

3 years ago

Could use the help! thanks again!

love history [14]

Answer:

Beth is incorrect.

It is a translate to the right 5 units and up 1 unit.

When we solve x-5=0 we get x=5, not x=-5 which says we go right 5 units.

When we plug in 5 into the expression for g, we get 1 which means go up 1 as well.

Step-by-step explanation:

So $g(x)=\sqrt{x-5}+1$ is actually a translated 5 units and up 1 unit. Why?

Let's take there point (0,0) and figure out what the new point is on the translated graph.

We need to figure out when the inside of our square root for g is 0. This is where the graph of g will start at and continue on.

x-5=0 when x=5 ( I added 5 on both sides).

So let's plug in 5 to see what the new point is.

$g(5)=\sqrt{5-5}+1$

$g(5)=\sqrt{0}+1$

$g(5)=0+1$

$g(5)=1$

So the new graph, g, starts at the point (5,1).

5 0

3 years ago

Evaluate ab + c for a = 2, b = 3, and c = 4. 9 10 27

Lilit [14]

Given that a = 2, b = 3, and c = 4.

To evaluate ab+c, we will plug given values as shown below

ab+c

=2*3+4

=6+4

=10

Hence final answer is 10.

6 0

2 years ago

2 A boat costs $18,800 and decreases in value by 12% per year. How much will the boat be worth after 13 years?

11111nata11111 [884]

$\bf \qquad \textit{Amount for Exponential Decay} \\\\ A=P(1 - r)^t\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{initial amount}\dotfill &18800\\ r=rate\to 12\%\to \frac{12}{100}\dotfill &0.12\\ t=\textit{elapsed time}\dotfill &13\\ \end{cases} \\\\\\ A=18800(1-0.12)^{13}\implies A=18800(0.88)^{13}\implies A\approx 3568.0636019$

6 0

3 years ago